Class 12 Chemistry Haloalkanes and Haloarenes

Chapter 6: Haloalkanes and Haloarenes

Part 1 – Introduction, Classification & Nomenclature (Class 12 Notes)

1. Organohalogen Compounds

Organic compounds in which one or more hydrogen atoms are replaced by F, Cl, Br, or I are called organohalogen compounds.

Two Main Types

HaloalkanesHaloarenes
Halogen attached to an sp³ carbon of an alkyl groupHalogen attached directly to an sp² carbon of a benzene ring

Examples

  • CH₃Cl → Haloalkane
  • C₂H₅Br → Haloalkane
  • C₆H₅Cl (Chlorobenzene) → Haloarene

2. Importance

Organohalogen compounds are widely used as:

  • Industrial solvents
  • Refrigerants
  • Medicines
  • Anaesthetics
  • Pesticides
  • Starting materials for organic synthesis

Some naturally occurring compounds also contain halogens.


3. Classification of Halo Compounds

A. Based on Number of Halogen Atoms

TypeMeaningExample
MonohaloOne halogen atomCH₃Cl
DihaloTwo halogensCH₂Cl₂
TrihaloThree halogensCHCl₃
PolyhaloMore than three halogensCCl₄

B. Compounds with sp³ C–X Bond

(i) Alkyl Halides (Haloalkanes)

General Formula:

R–X

where

  • R = Alkyl group
  • X = F, Cl, Br, I

Example:

CH₃CH₂Cl


Classification of Alkyl Halides

Depends on the carbon attached to halogen.

Primary (1°)

Halogen attached to carbon connected with only one carbon.

Example:

CH₃CH₂Cl


Secondary (2°)

Halogen attached to carbon connected with two carbons.

Example:

CH₃CHClCH₃


Tertiary (3°)

Halogen attached to carbon connected with three carbons.

Example:

(CH₃)₃CCl


Easy Memory Trick

Count the number of carbon atoms attached to the carbon bearing the halogen.


(ii) Allylic Halides

Halogen attached to an sp³ carbon adjacent to a double bond.

General Structure

CH₂=CH–CH₂X

Example

CH₂=CHCH₂Br

(Allyl bromide)


(iii) Benzylic Halides

Halogen attached to an sp³ carbon attached to a benzene ring.

General Structure

C₆H₅CH₂X

Example

C₆H₅CH₂Cl

(Benzyl chloride)


C. Compounds with sp² C–X Bond

(i) Vinylic Halides

Halogen attached directly to a carbon of a double bond.

Example

CH₂=CHCl

(Vinyl chloride)


(ii) Aryl Halides

Halogen attached directly to the benzene ring.

Example

C₆H₅Cl

(Chlorobenzene)


Quick Comparison

CompoundHalogen Attached To
Alkyl halidesp³ carbon
Allylic halidesp³ carbon next to C=C
Benzylic halidesp³ carbon next to benzene
Vinylic halidesp² carbon of C=C
Aryl halidesp² carbon of benzene

Exam Tip: Students often confuse benzylic and aryl halides. In benzylic halides, the halogen is not directly attached to the benzene ring; in aryl halides, it is attached directly.


4. Geminal and Vicinal Dihalides

Geminal (Gem) Dihalides

Both halogen atoms are present on the same carbon atom.

Example

CH₃–CHCl₂


Vicinal (Vic) Dihalides

Halogen atoms are present on adjacent carbon atoms.

Example

CH₂Cl–CH₂Cl


Memory Trick

  • GemSame carbon
  • VicNeighbouring carbons

5. Nomenclature

Common Name

Rule:

Alkyl group + Halide

Example

CH₃Cl

→ Methyl chloride


IUPAC Name

Rule:

Treat halogen as a substituent.

Example

CH₃CH₂Br

→ Bromoethane


Important Examples

StructureCommon NameIUPAC Name
CH₃ClMethyl chlorideChloromethane
CH₃CH₂ClEthyl chlorideChloroethane
CH₂Cl₂Methylene chlorideDichloromethane
CHCl₃ChloroformTrichloromethane
CCl₄Carbon tetrachlorideTetrachloromethane
CH₂=CHClVinyl chlorideChloroethene
CH₂=CHCH₂BrAllyl bromide3-Bromopropene
C₆H₅CH₂ClBenzyl chlorideChlorophenylmethane

6. Rules for IUPAC Naming

  1. Select the longest carbon chain.
  2. Number the chain to give the halogen the lowest possible number.
  3. Write the halogen as a prefix:
    • Fluoro
    • Chloro
    • Bromo
    • Iodo
  4. Arrange different substituents alphabetically.
  5. Use di-, tri-, tetra- when identical halogens are present.

Example

CH₃CH₂CH(Cl)CH₃

Longest chain = Butane

Halogen at carbon 2

Name = 2-Chlorobutane


Example

(CH₃)₃CBr

Longest chain = Propane

Substituents:

  • Bromo at C-2
  • Methyl at C-2

Name = 2-Bromo-2-methylpropane


NCERT Important Facts

  • Haloalkanes contain sp³ C–X bonds.
  • Haloarenes contain sp² C–X bonds.
  • Primary, secondary and tertiary haloalkanes depend on the carbon attached to halogen, not the total number of carbons.
  • Geminal = same carbon.
  • Vicinal = adjacent carbons.
  • Allylic and benzylic halides are generally more reactive than ordinary alkyl halides because of the stability of the intermediates formed in reactions.

1-Minute Revision

  • Haloalkane: Halogen on sp³ carbon.
  • Haloarene: Halogen on benzene carbon (sp²).
  • Primary: Halogen carbon attached to 1 carbon.
  • Secondary: Attached to 2 carbons.
  • Tertiary: Attached to 3 carbons.
  • Allylic: Next to C=C.
  • Benzylic: Next to benzene.
  • Vinylic: On C=C.
  • Aryl: On benzene ring.
  • Geminal: Same carbon.
  • Vicinal: Adjacent carbons.

Part 2 – Nature of C–X Bond & Preparation of Haloalkanes

1. Nature of the Carbon–Halogen (C–X) Bond

Why is the C–X bond polar?

Halogens are more electronegative than carbon.

Therefore,

  • Carbon acquires a partial positive charge (δ⁺)
  • Halogen acquires a partial negative charge (δ⁻)
Cδ+  ——  Xδ−

Because of this polarity:

  • Carbon becomes electron deficient (electrophilic).
  • It is easily attacked by nucleophiles.
  • Haloalkanes readily undergo substitution reactions.

2. Effect of Halogen Size

Moving down Group 17:

F → Cl → Br → I

Atomic size increases.

Therefore,

  • C–X bond length increases.
  • Bond strength decreases.
  • Bond becomes easier to break.

Order of Bond Length

C–F < C–Cl < C–Br < C–I

Reason:
Larger halogen atoms form longer bonds.


Order of Bond Strength (Bond Enthalpy)

C–F > C–Cl > C–Br > C–I

Reason:
Shorter bonds are stronger.


Easy Memory Trick

Longer bond = Weaker bond = More reactive


Reactivity Towards Bond Breaking

RI > RBr > RCl >> RF

Reason:

  • Iodine leaves most easily (best leaving group).
  • Fluorine forms the strongest bond and is the least reactive.

3. Methods of Preparation of Haloalkanes

There are four important methods in NCERT.

Alcohols
     ↓
Haloalkanes

Hydrocarbons
     ↓
Haloalkanes

Alkenes
     ↓
Haloalkanes

Halogen Exchange
     ↓
Haloalkanes

Method 1: From Alcohols (Most Important)

Alcohols are the best starting materials because they are easily available.

General reaction:

ROH  →  RX

The –OH group is replaced by a halogen atom.


Reagents Used

(i) Hydrogen Halides

  • HCl
  • HBr
  • HI

(ii) Phosphorus Halides

  • PCl₃
  • PCl₅
  • PBr₃

(iii) Thionyl Chloride (SOCl₂)

Most important reagent for boards.

Reaction

ROH + SOCl₂

↓

RCl + SO₂↑ + HCl↑

Why is SOCl₂ preferred?

Because both by-products,

  • SO₂
  • HCl

are gases and escape from the reaction mixture.

Hence,

  • Product remains almost pure.
  • Purification becomes easy.

Exam Question: Why is SOCl₂ preferred over HCl?

Answer: Gaseous by-products (SO₂ and HCl) escape, giving pure alkyl chloride.


Lucas Reagent

For preparing alkyl chlorides using HCl.

Lucas reagent =

Conc. HCl + Anhydrous ZnCl₂

ZnCl₂ acts as a catalyst.


Reactivity of Alcohols

3° Alcohol > 2° Alcohol > 1° Alcohol

Reason:

Tertiary alcohols form more stable carbocations and react faster.


Method 2: From Hydrocarbons

(A) From Alkanes

Reaction:

Free radical halogenation.

Example

CH₄ + Cl₂

UV light

↓

CH₃Cl + HCl

Characteristics

  • Free radical mechanism
  • Gives a mixture of products
  • Low yield of desired compound

Not preferred for laboratory preparation because many isomers and polyhalogenated products are formed.


(B) From Alkenes

Two important reactions.


(i) Addition of Hydrogen Halides

General reaction

Alkene + HX

↓

Haloalkane

Example

CH₃CH=CH₂ + HBr

↓

CH₃CHBrCH₃

Major product follows Markovnikov’s rule.

Markovnikov Rule:
Hydrogen attaches to the carbon already having more hydrogen atoms, while the halogen goes to the more substituted carbon.


(ii) Addition of Halogens

Example

CH₂=CH₂ + Br₂

↓

CH₂Br–CH₂Br

Product:

Vicinal dibromide.


Important Application

Bromine solution loses its reddish-brown colour in the presence of a double bond.

Therefore,

Bromine test is used to detect unsaturation (C=C).


Method 3: Halogen Exchange Reactions

Very important for board exams.


(A) Finkelstein Reaction

Used for preparing alkyl iodides.

Reaction

RCl or RBr + NaI
      Dry acetone
↓

RI + NaCl/NaBr

Key Points

  • Reagent: NaI
  • Solvent: Dry acetone
  • NaCl or NaBr precipitates out.
  • The precipitation drives the reaction forward (Le Chatelier’s principle).

(B) Swarts Reaction

Used for preparing alkyl fluorides.

Reaction

RCl/RBr

+ AgF / SbF₃ / Hg₂F₂ / CoF₂

↓

RF

Remember

Swarts → Fluorides


Named Reactions Summary

ReactionProduct FormedReagent
Alcohol → Alkyl chlorideRClSOCl₂ / HCl
FinkelsteinRINaI + dry acetone
SwartsRFAgF, SbF₃, Hg₂F₂, CoF₂
Free radical halogenationHaloalkaneCl₂/Br₂ + UV light
Alkene + HXHaloalkaneHCl, HBr, HI
Alkene + Br₂Vicinal dibromideBr₂/CCl₄

NCERT Important Facts

  • C–X bond is polar because halogens are more electronegative than carbon.
  • Bond length increases from C–F to C–I.
  • Bond strength decreases from C–F to C–I.
  • Reactivity: RI > RBr > RCl >> RF.
  • SOCl₂ is the preferred reagent for preparing alkyl chlorides.
  • Lucas reagent = Conc. HCl + ZnCl₂.
  • 3° alcohol > 2° alcohol > 1° alcohol in reactivity.
  • Finkelstein reaction prepares alkyl iodides.
  • Swarts reaction prepares alkyl fluorides.
  • Bromine decolourisation is a test for unsaturation.

30-Second Revision

  • C–X bond is polar (Cδ⁺–Xδ⁻).
  • Bond length: C–F < C–Cl < C–Br < C–I.
  • Bond strength: C–F > C–Cl > C–Br > C–I.
  • Reactivity: RI > RBr > RCl >> RF.
  • Best reagent for RCl: SOCl₂.
  • Finkelstein → RI.
  • Swarts → RF.
  • Alkene + Br₂ gives vicinal dibromide.
  • Bromine test detects C=C double bonds.

Part 3 – Preparation of Haloarenes & Physical Properties

1. Preparation of Haloarenes

Haloarenes cannot be prepared by ordinary substitution reactions used for haloalkanes because the aryl C–X bond is stronger. NCERT describes the following important methods.


Method 1: Direct Halogenation of Benzene (Most Important)

Benzene reacts with chlorine or bromine in the presence of a Lewis acid catalyst.

Chlorination

Benzene + Cl₂
      FeCl₃ / AlCl₃
↓

Chlorobenzene + HCl

Bromination

Benzene + Br₂
      FeBr₃
↓

Bromobenzene + HBr

Role of Catalyst

  • FeCl₃, AlCl₃ and FeBr₃ are Lewis acids.
  • They generate the electrophile (Cl⁺ or Br⁺), which attacks the benzene ring.

Exam Point: Chlorination or bromination of benzene does not occur easily without a catalyst.


Method 2: From Diazonium Salts

This method is mainly used to prepare chloro-, bromo- and iodobenzene.

Aromatic diazonium salts are obtained from aromatic amines and then converted into haloarenes.


(A) Sandmeyer Reaction ⭐

Copper(I) salts replace the diazonium group by Cl or Br.

Reactions

ArN₂⁺Cl⁻ + CuCl

↓

ArCl + N₂
ArN₂⁺Cl⁻ + CuBr

↓

ArBr + N₂

Key Points

  • Catalyst: CuCl or CuBr
  • Nitrogen gas is evolved.
  • Used for preparing chlorobenzene and bromobenzene.

(B) Gattermann Reaction

Uses copper powder and hydrogen halides.

ArN₂⁺Cl⁻

Cu + HCl

↓

ArCl

or

Cu + HBr

↓

ArBr

Difference

SandmeyerGattermann
CuCl/CuBr usedCu powder + HCl/HBr
More commonLess common

(C) Preparation of Iodobenzene

ArN₂⁺Cl⁻ + KI

↓

ArI + N₂

No copper catalyst is required.


(D) Preparation of Fluorobenzene

Balz–Schiemann Reaction ⭐

Diazonium tetrafluoroborate

Heat

↓

Fluorobenzene + BF₃ + N₂

This is the preferred method for preparing aryl fluorides.


Named Reactions Summary

ReactionProductReagent
SandmeyerArCl / ArBrCuCl / CuBr
GattermannArCl / ArBrCu + HCl/HBr
KI reactionArIKI
Balz–SchiemannArFDiazonium tetrafluoroborate + Heat

2. Physical Properties

Physical properties depend mainly on:

  • Molecular mass
  • Shape of molecule
  • Intermolecular forces

(A) Physical State

Lower Members

Usually gases or volatile liquids.

Examples

  • CH₃Cl → Gas
  • C₂H₅Cl → Gas

Higher Members

Generally liquids or solids because molecular mass increases.


(B) Colour

Most haloalkanes and haloarenes are

  • Colourless
  • Sweet smelling

Exposure to light for a long time may cause slight yellowing due to decomposition.


(C) Solubility

In Water

Haloalkanes and haloarenes are almost insoluble.

Why?

Water molecules are strongly held together by hydrogen bonding.

Halo compounds cannot form hydrogen bonds with water.

The energy released during hydration is not sufficient to break the hydrogen bonds already present in water.

Hence,

Very low solubility in water.


In Organic Solvents

They dissolve readily in

  • Benzene
  • Ether
  • Chloroform
  • Carbon tetrachloride

Reason:

Like dissolves like.


(D) Boiling Point

Boiling point depends on

  • Molecular mass
  • Surface area
  • Strength of intermolecular forces

Effect of Halogen

As halogen size increases,

RF < RCl < RBr < RI

Boiling point increases because:

  • Molecular mass increases.
  • Van der Waals forces become stronger.

Effect of Carbon Chain

Longer carbon chain

Higher molecular mass

Higher boiling point.


Effect of Branching

More branching

Smaller surface area

Weaker intermolecular attraction

Lower boiling point.

Example:

n-Butyl chloride

>

tert-Butyl chloride

(E) Density

Density generally increases with heavier halogens.

Fluoro < Chloro < Bromo < Iodo

Most alkyl chlorides are lighter than water.

Many bromides and iodides are denser than water.


(F) Melting Point

Melting point depends on:

  • Molecular symmetry
  • Crystal packing

More symmetrical molecules pack better in crystals and therefore usually have higher melting points.


NCERT Important Facts

  • Chlorination of benzene requires FeCl₃/AlCl₃ catalyst.
  • Sandmeyer reaction uses CuCl or CuBr.
  • Gattermann reaction uses Cu powder + HCl/HBr.
  • Balz–Schiemann reaction is used to prepare aryl fluorides.
  • Halo compounds are insoluble in water because they cannot form hydrogen bonds.
  • Boiling point increases with molecular mass.
  • Branching decreases boiling point.
  • Heavier halogens generally increase density.

One-Page Revision

Preparation of Haloarenes

MethodProduct
Benzene + Cl₂/FeCl₃Chlorobenzene
Benzene + Br₂/FeBr₃Bromobenzene
SandmeyerArCl / ArBr
GattermannArCl / ArBr
KIArI
Balz–SchiemannArF

Physical Properties

PropertyTrend
Water solubilityVery low
Organic solvent solubilityHigh
Boiling pointIncreases with molecular mass
BranchingDecreases boiling point
DensityRF < RCl < RBr < RI
ColourMostly colourless

Part 4 – Chemical Reactions of Haloalkanes (Most Important Section)

1. Why are Haloalkanes Reactive?

The carbon atom bonded to halogen is electron deficient (δ⁺) because the C–X bond is polar.

Therefore:

  • Nucleophiles attack the carbon atom.
  • Halogen leaves as a halide ion (X⁻).

Thus, haloalkanes mainly undergo:

  1. Nucleophilic substitution reactions
  2. Elimination reactions

2. Nucleophilic Substitution Reactions

What is a Nucleophile?

A nucleophile is an electron-rich species that donates an electron pair.

Common Nucleophiles

NucleophileProduct Formed
OH⁻Alcohol
CN⁻Nitrile
NH₃Amine
RO⁻Ether
I⁻Alkyl iodide
SH⁻Thiol

General Reaction

R–X + Nu⁻  →  R–Nu + X⁻

Here,

  • X⁻ = Leaving group
  • Nu⁻ = Nucleophile

3. Factors Affecting Reactivity

Reactivity depends on:

  • Strength of C–X bond
  • Stability of intermediate (if formed)
  • Nature of nucleophile
  • Structure of alkyl halide

4. SN2 Reaction (Bimolecular Nucleophilic Substitution)

Meaning

  • S = Substitution
  • N = Nucleophilic
  • 2 = Two species take part in the rate-determining step.

Mechanism

  • Nucleophile attacks from the back side of the carbon atom.
  • Carbon–halogen bond breaks at the same time.
  • Only one step is involved.
  • No carbocation is formed.

Characteristics

  • One-step reaction
  • Backside attack
  • Simultaneous bond making and bond breaking
  • No intermediate

Order of Reactivity

CH₃X > 1° > 2° >> 3°

Reason

Less crowding around the carbon allows easier attack by the nucleophile.

Hence,

  • Methyl halides react fastest.
  • Tertiary halides react slowest.

Stereochemistry

SN2 causes inversion of configuration (Walden inversion).

This happens because the nucleophile attacks from the opposite side of the leaving group.


5. SN1 Reaction (Unimolecular Nucleophilic Substitution)

Meaning

  • S = Substitution
  • N = Nucleophilic
  • 1 = One species is involved in the rate-determining step.

Mechanism

Step 1 (Slow)

The C–X bond breaks.

R–X

↓

R⁺ + X⁻

A carbocation is formed.


Step 2 (Fast)

The nucleophile attacks the carbocation.

R⁺ + OH⁻

↓

ROH

Characteristics

  • Two-step reaction
  • Carbocation intermediate formed
  • First step is slow
  • Second step is fast

Reactivity Order

3° > 2° > 1° > CH₃

Reason

More stable carbocations form more easily.

  • Tertiary carbocation → Most stable
  • Primary carbocation → Least stable

Stereochemistry

Since the carbocation is planar, the nucleophile can attack from either side.

Hence, both configurations are formed.

Result:

Racemization (mixture of enantiomers).


6. SN1 vs SN2 (Very Important)

PropertySN1SN2
StepsTwoOne
IntermediateCarbocationNone
Rate depends onHaloalkane onlyHaloalkane + nucleophile
Reactivity order3° > 2° > 1°CH₃ > 1° > 2° > 3°
StereochemistryRacemizationInversion
Favoured by3° halidesMethyl & 1° halides

7. Elimination Reaction (β-Elimination)

When haloalkanes are heated with alcoholic KOH, a hydrogen atom and the halogen atom are removed from adjacent carbon atoms.

An alkene is formed.

General Reaction

R–CH₂–CH₂–X
      Alcoholic KOH
Heat
↓

R–CH=CH₂ + KX + H₂O

Example

CH₃CH₂Br

Alcoholic KOH

↓

CH₂=CH₂

Why is it Called β-Elimination?

  • Halogen leaves from the α-carbon.
  • Hydrogen is removed from the β-carbon.

8. Competing Reactions

ReagentMajor Product
Aqueous KOHAlcohol
Alcoholic KOHAlkene

Easy Memory

  • Water → Substitution
  • Alcohol → Elimination

9. Reaction with Magnesium

Haloalkanes react with magnesium in dry ether to form Grignard reagents.

R–X + Mg
Dry ether
↓

R–MgX

Importance

Grignard reagents are extremely useful for preparing:

  • Alcohols
  • Carboxylic acids
  • Hydrocarbons
  • Higher organic compounds

Exam Point: Grignard reagents react immediately with water, so they must be prepared in absolutely dry ether.


10. Wurtz Reaction ⭐

Two alkyl halide molecules react with sodium metal in dry ether.

2R–X + 2Na
Dry ether
↓

R–R + 2NaX

Product

Higher alkane

Example

2CH₃Br + 2Na

↓

C₂H₆ + 2NaBr

Uses

  • Preparation of symmetrical alkanes.
  • Not suitable for unsymmetrical alkanes because a mixture of products is formed.

11. NCERT Reaction Summary

ReagentProduct
Aqueous KOHAlcohol
Alcoholic KOHAlkene
NH₃Amine
KCNNitrile
AgCNIsocyanide
NaI (dry acetone)Alkyl iodide
Mg/Dry etherGrignard reagent
Na/Dry etherHigher alkane (Wurtz reaction)

Board Exam Highlights

Must Remember

  • SN1 → Carbocation intermediate.
  • SN2 → Backside attack.
  • SN2 gives Walden inversion.
  • SN1 gives racemization.
  • Aqueous KOH → Alcohol.
  • Alcoholic KOH → Alkene.
  • Grignard reagent must be prepared in dry ether.
  • Wurtz reaction prepares symmetrical alkanes.

One-Page Revision

Reactivity Order

SN1

3° > 2° > 1° > CH₃

SN2

CH₃ > 1° > 2° > 3°

Key Named Reactions

ReactionProduct
WurtzHigher alkane
GrignardR–MgX
Aqueous KOHAlcohol
Alcoholic KOHAlkene
KCNNitrile
NH₃Amine

Part 5 – Chemical Reactions of Haloarenes

1. Why are Haloarenes Less Reactive than Haloalkanes?

Haloarenes (aryl halides) are much less reactive towards nucleophilic substitution reactions compared to haloalkanes.

Example:

Chlorobenzene reacts much slower than chloroethane.


Reasons for Low Reactivity of Haloarenes

(i) Resonance Effect

In chlorobenzene, the lone pair of chlorine participates in resonance with the benzene ring.

This gives the C–Cl bond a partial double bond character.

Therefore:

  • Bond becomes shorter.
  • Bond becomes stronger.
  • Breaking the bond becomes difficult.

(ii) Hybridisation of Carbon

In haloalkanes:

  • Carbon attached to halogen is sp³ hybridised.

In haloarenes:

  • Carbon attached to halogen is sp² hybridised.

The sp² carbon has more s-character, making it more electronegative and holding the C–X bond more strongly.


(iii) Instability of Phenyl Cation

SN1 reaction requires formation of a carbocation.

Formation of phenyl cation is highly unstable.

Therefore, haloarenes do not easily undergo SN1 reactions.


(iv) Difficulty in Backside Attack

SN2 reaction requires attack from the backside.

In haloarenes:

  • Benzene ring blocks the backside attack.
  • Therefore SN2 reaction becomes difficult.

2. Nucleophilic Substitution in Haloarenes

Although haloarenes are less reactive, under severe conditions they can undergo nucleophilic substitution.


Example: Chlorobenzene to Phenol

Reaction:

C₆H₅Cl + NaOH

High temperature and pressure

↓

C₆H₅OH + NaCl

Conditions:

  • Temperature: about 623 K
  • Pressure: about 300 atm

Product:

Phenol


3. Effect of Electron Withdrawing Groups

Electron withdrawing groups increase the reactivity of haloarenes towards nucleophilic substitution.

Examples:

  • –NO₂
  • –CN
  • –COOH

Position Effect of Nitro Group

Nitro group increases reaction speed when present at:

  • Ortho position
  • Para position

It decreases when present at meta position.


Example:

p-Nitrochlorobenzene

reacts faster than chlorobenzene.

Reason:

The nitro group stabilises the intermediate formed during substitution.


4. Electrophilic Substitution Reactions of Haloarenes

Haloarenes contain a benzene ring, therefore they undergo electrophilic substitution reactions.

Common reactions:

  1. Halogenation
  2. Nitration
  3. Sulphonation
  4. Friedel-Crafts reaction

(A) Halogenation

Chlorobenzene reacts with chlorine in presence of FeCl₃.

Reaction:

C₆H₅Cl + Cl₂

FeCl₃

↓

o-Dichlorobenzene + p-Dichlorobenzene

Products:

  • Ortho isomer
  • Para isomer

(B) Nitration

Reaction:

Chlorobenzene + HNO₃

H₂SO₄

↓

o-Nitrochlorobenzene + p-Nitrochlorobenzene

(C) Sulphonation

Reaction:

Chlorobenzene + H₂SO₄

↓

o-Chlorobenzenesulphonic acid
+
p-Chlorobenzenesulphonic acid

(D) Friedel-Crafts Reaction

Haloarenes generally do not undergo Friedel-Crafts alkylation and acylation.

Reason:

The halogen atom reduces the reactivity of the benzene ring.


5. Directive Influence of Halogen Atom

Halogens show:

  • −I effect (electron withdrawing)
  • +R effect (resonance donating)

Because of these opposite effects:

Overall effect:

  • Ring becomes less reactive towards electrophilic substitution.
  • Halogen directs incoming groups to ortho and para positions.

Important Point

Halogens are:

  • Deactivating groups
  • Ortho-para directing groups

This is an important board exam concept.


6. Reactions with Metals

Haloarenes react with metals to form useful products.


(A) Fittig Reaction ⭐

Two molecules of aryl halides react with sodium metal in dry ether.

General reaction:

2Ar–X + 2Na

Dry ether

↓

Ar–Ar + 2NaX

Example:

2C₆H₅Cl + 2Na

↓

Biphenyl + 2NaCl

Product:

Biphenyl


(B) Wurtz–Fittig Reaction ⭐

Aryl halide reacts with alkyl halide in presence of sodium metal.

Reaction:

Ar–X + R–X + 2Na

Dry ether

↓

Ar–R + 2NaX

Example:

C₆H₅Cl + CH₃Cl + 2Na

↓

Toluene + 2NaCl

Product:

Alkyl benzene


Fittig vs Wurtz–Fittig

ReactionReactantsProduct
FittigTwo aryl halidesBiaryl
WurtzTwo alkyl halidesAlkane
Wurtz–FittigAlkyl + aryl halideAlkyl benzene

7. Important Comparison: Haloalkanes vs Haloarenes

PropertyHaloalkanesHaloarenes
Carbon typesp³sp²
C–X bondWeakerStronger
ReactivityHigherLower
SN1 reactionEasy (3°)Difficult
SN2 reactionCommonDifficult
ExampleCH₃ClC₆H₅Cl

NCERT Important Facts

  • Haloarenes are less reactive because the C–X bond has partial double bond character.
  • SN1 reaction is difficult due to unstable phenyl carbocation.
  • SN2 reaction is difficult due to steric hindrance and resonance.
  • Electron withdrawing groups increase nucleophilic substitution.
  • Nitro group at ortho and para positions increases reactivity.
  • Halogens are deactivating but ortho-para directing.
  • Fittig reaction gives biphenyl.
  • Wurtz–Fittig reaction gives alkyl benzene.
  • Chlorobenzene can be converted to phenol under severe conditions.

Quick Revision Sheet

Haloarenes

Low reactivity because:

  1. Resonance strengthens C–X bond.
  2. sp² carbon forms stronger bond.
  3. Phenyl cation is unstable.
  4. Backside attack is difficult.

Named Reactions

ReactionProduct
FittigBiphenyl
Wurtz–FittigAlkyl benzene
Chlorobenzene + NaOHPhenol
NitrationNitro derivatives
HalogenationOrtho/para halo products

Part 6 – Polyhalogen Compounds & Complete Chapter Revision

1. Polyhalogen Compounds

Organic compounds containing more than one halogen atom are called polyhalogen compounds.

Examples:

  • Dichloromethane (CH₂Cl₂)
  • Chloroform (CHCl₃)
  • Carbon tetrachloride (CCl₄)
  • Freons
  • DDT

Many of these compounds have important industrial applications.


2. Dichloromethane (Methylene Chloride)

Formula:

CH₂Cl₂

Preparation:

Prepared by chlorination of methane.

CH₄ + Cl₂

hv

↓

CH₃Cl

↓

CH₂Cl₂

Properties

  • Colourless liquid
  • Sweet smell
  • Volatile
  • Slightly soluble in water
  • Soluble in organic solvents

Uses

Dichloromethane is used as:

  • Solvent for extraction processes
  • Solvent in paints and varnishes
  • Cleaning agent
  • Used in aerosol formulations

3. Chloroform (Trichloromethane)

Formula:

CHCl₃


Preparation

Chloroform is prepared by chlorination of methane.

CH₄ + Cl₂

↓

CH₃Cl

↓

CH₂Cl₂

↓

CHCl₃

Important Reaction

Chloroform gets oxidised in air and sunlight to form poisonous phosgene gas (COCl₂).

Reaction:

CHCl₃ + O₂

↓

COCl₂ + HCl

Therefore:

  • Chloroform is stored in dark-coloured bottles.
  • A small amount of ethanol is added as a stabiliser.

Ethanol converts phosgene into harmless compounds.


Uses

Earlier:

  • Used as an anaesthetic.

Present uses:

  • Solvent for organic compounds
  • Chemical preparation

4. Carbon Tetrachloride

Formula:

CCl₄


Properties

  • Colourless liquid
  • Non-flammable
  • Toxic
  • Insoluble in water

Uses

Previously used as:

  • Fire extinguishing agent
  • Solvent

However, its use has reduced because it damages the ozone layer.


5. Freons (Chlorofluorocarbons)

Freons are compounds containing:

  • Carbon
  • Chlorine
  • Fluorine

General formula:

CCl₂F₂

(Example: Freon-12)


Uses

Freons are used as:

  • Refrigerants in refrigerators and air conditioners
  • Propellants in aerosol sprays

Environmental Effect

Freons release chlorine radicals in the atmosphere.

These radicals destroy ozone molecules.

Reaction:

Cl· + O₃ → ClO· + O₂

Ozone layer depletion increases harmful UV radiation reaching Earth.


6. DDT (Dichlorodiphenyltrichloroethane)

Formula:

C₁₄H₉Cl₅

DDT is a powerful insecticide.


Uses

Used for controlling:

  • Mosquitoes
  • Agricultural pests

Problems

DDT is:

  • Non-biodegradable
  • Persistent in the environment
  • Accumulates in living organisms

It enters food chains and causes harmful effects.


Important Polyhalogen Compounds Table

CompoundFormulaImportant Use
DichloromethaneCH₂Cl₂Solvent
ChloroformCHCl₃Solvent, anaesthetic (earlier)
Carbon tetrachlorideCCl₄Fire extinguisher, solvent
FreonsCCl₂F₂Refrigerants
DDTC₁₄H₉Cl₅Insecticide

COMPLETE CHAPTER QUICK REVISION

1. Classification

Haloalkanes

Halogen attached to sp³ carbon

Example:

CH₃Cl


Haloarenes

Halogen attached directly to benzene ring.

Example:

C₆H₅Cl


2. Important Orders

Bond Length

C–F < C–Cl < C–Br < C–I

Bond Strength

C–F > C–Cl > C–Br > C–I

Reactivity of Haloalkanes

RI > RBr > RCl >> RF


3. Preparation Reactions

ReactionImportant Point
Alcohol + SOCl₂Best method for alkyl chloride
FinkelsteinPreparation of alkyl iodide
SwartsPreparation of alkyl fluoride
SandmeyerArCl/ArBr preparation
Balz–SchiemannArF preparation

4. SN1 and SN2 Summary

FeatureSN1SN2
StepsTwoOne
IntermediateCarbocationNone
RateDepends on haloalkaneDepends on haloalkane + nucleophile
Favoured3° halidesMethyl and 1° halides
StereochemistryRacemisationInversion

5. Reactions with KOH

Aqueous KOH

Haloalkane → Alcohol

Alcoholic KOH

Haloalkane → Alkene

6. Important Named Reactions

Wurtz Reaction

2R–X + 2Na → R–R + 2NaX

Product:

Symmetrical alkane


Fittig Reaction

2Ar–X + 2Na → Ar–Ar + 2NaX

Product:

Biphenyl


Wurtz–Fittig Reaction

Ar–X + R–X + 2Na → Ar–R + 2NaX

Product:

Alkyl benzene


Sandmeyer Reaction

Diazonium salt + CuCl/CuBr

→ Haloarene


Balz–Schiemann Reaction

Diazonium salt

→ Fluorobenzene


MOST IMPORTANT BOARD QUESTIONS

Q1. Why is chlorobenzene less reactive than chloroethane?

Answer:

  • C–Cl bond in chlorobenzene has partial double bond character due to resonance.
  • Carbon is sp² hybridised.
  • Bond is stronger and difficult to break.

Q2. Why is SOCl₂ preferred for preparing alkyl chlorides?

Answer:

SOCl₂ produces gaseous SO₂ and HCl which escape, leaving pure alkyl chloride.


Q3. Give reason:

Haloalkanes are insoluble in water.

Answer:

They cannot form strong hydrogen bonds with water molecules.


Q4. Why do tertiary haloalkanes undergo SN1 reaction faster?

Answer:

They form more stable tertiary carbocations.


Q5. Why are halogens ortho-para directing but deactivating?

Answer:

  • −I effect decreases ring activity.
  • +R effect directs substitution to ortho and para positions.

Final 10-Minute Revision

Remember these keywords:

  • C–X bond polarity → Nucleophilic attack
  • SOCl₂ → Pure alkyl chloride
  • Finkelstein → Iodide
  • Swarts → Fluoride
  • SN1 → Carbocation → Racemisation
  • SN2 → Backside attack → Inversion
  • Alcoholic KOH → Elimination
  • Mg + dry ether → Grignard reagent
  • Wurtz → Alkane
  • Fittig → Biphenyl
  • Wurtz–Fittig → Alkyl benzene
  • Freons → Ozone depletion
  • DDT → Non-biodegradable insecticide