Class 7 Maths Worksheet – Comparing Quantities

Part 1: Fill in the Blanks

1. 25% of 200 = ______
2. 40% of 150 = ______
3. 15% of 500 = ______
4. 60% of 300 = ______
5. 10% of 250 = ______

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Part 2: Express as Percent

6. 45 out of 60 = ______%
7. 120 out of 200 = ______%
8. 75 out of 150 = ______%
9. 90 out of 120 = ______%
10. 36 out of 90 = ______%

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Part 3: Profit and Loss

11. A shopkeeper buys a pen for ₹50 and sells it for ₹60. Find the profit and profit %.
12. A book is bought for ₹120 and sold for ₹100. Find the loss and loss %.
13. A bicycle is purchased for ₹4000 and sold for ₹4500. Find the profit %.
14. A bag bought for ₹800 is sold for ₹720. Find the loss %.
15. If a toy is bought for ₹150 and sold for ₹180, find the profit %.

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Part 4: Discount

16. A shirt costs ₹1200. If there is a 25% discount, find the selling price.
17. A bag costs ₹500. If the discount is 10%, find the selling price.
18. A watch costs ₹1500 and is sold at 20% off. Find the discounted price.
19. A pair of shoes costs ₹2000 and the shopkeeper gives 15% discount. Find the selling price.
20. A jacket costs ₹1800. Find the price after 30% discount.

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Part 5: Ratio and Proportion

21. The ratio of boys to girls in a class is 3:4. If there are 12 boys, how many girls are there?
22. A recipe requires sugar and flour in the ratio 2:5. If 4 kg of sugar is used, how much flour is needed?
23. Divide ₹360 among A, B, and C in the ratio 3:4:5. Find each share.
24. The ratio of red balls to blue balls is 5:3. If there are 40 red balls, how many blue balls?
25. A map scale shows 1 cm = 5 km. If two towns are 12 cm apart on the map, what is the actual distance?

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Part 6: Word Problems

26. A shopkeeper sold an article at 20% profit for ₹600. Find the cost price.
27. A fruit seller bought 50 kg apples at ₹40 per kg and sold at ₹50 per kg. Find the profit %.
28. A shopkeeper sold an item at a loss of 10% for ₹540. Find the cost price.
29. A school has 240 students. 60% are boys. How many girls are there?
30. A car’s price increased by 15% to ₹1,15,000. Find the original price.

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Part 7: Challenge (Optional)

31. A product is sold for ₹900 after giving a 10% discount. Find the marked price.
32. If 30% of a number is 60, find the number.
33. The population of a town increased by 12% in a year. If the population now is 56,000, find the population last year.
34. A shopkeeper gives 12% discount on an article and still earns a profit of 10%. If the cost price is ₹500, find the selling price.
35. The price of a book increases from ₹400 to ₹460. Find the percentage increase.

Class 7 – Comparing Quantities Worksheet Answers

Part 1: Fill in the Blanks

1. 25% of 200 = 50
2. 40% of 150 = 60
3. 15% of 500 = 75
4. 60% of 300 = 180
5. 10% of 250 = 25

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Part 2: Express as Percent

6. 45 out of 60 = 75%
7. 120 out of 200 = 60%
8. 75 out of 150 = 50%
9. 90 out of 120 = 75%
10. 36 out of 90 = 40%

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Part 3: Profit and Loss

11. CP = 50, SP = 60 → Profit = 10, Profit % = 20%
12. CP = 120, SP = 100 → Loss = 20, Loss % = 16.67%
13. CP = 4000, SP = 4500 → Profit = 500, Profit % = 12.5%
14. CP = 800, SP = 720 → Loss = 80, Loss % = 10%
15. CP = 150, SP = 180 → Profit = 30, Profit % = 20%

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Part 4: Discount

16. SP = 1200 – (25% of 1200) = 1200 – 300 = 900
17. SP = 500 – (10% of 500) = 500 – 50 = 450
18. SP = 1500 – (20% of 1500) = 1500 – 300 = 1200
19. SP = 2000 – (15% of 2000) = 2000 – 300 = 1700
20. SP = 1800 – (30% of 1800) = 1800 – 540 = 1260

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Part 5: Ratio and Proportion

21. Boys : Girls = 3:4 → 12 boys → Girls = (4/3) × 12 = 16 girls
22. Sugar : Flour = 2:5 → Sugar = 4 kg → Flour = (5/2) × 4 = 10 kg
23. Total = 360 → Ratio = 3:4:5 → Sum = 12

• A = 3/12 × 360 = 90
• B = 4/12 × 360 = 120
• C = 5/12 × 360 = 150

24. Red : Blue = 5:3 → Red = 40 → Blue = (3/5) × 40 = 24
25. Scale: 1 cm = 5 km → 12 cm = 12 × 5 = 60 km

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Part 6: Word Problems

26. SP = 600, Profit% = 20 → CP = 600 ÷ 1.2 = 500
27. CP = 50×40=2000, SP = 50×50=2500 → Profit = 500 → Profit% = 25%
28. SP = 540, Loss% = 10 → CP = 540 ÷ 0.9 = 600
29. Total students = 240 → Boys = 60% → Boys = 0.6×240=144 → Girls = 240–144=96
30. Increased price = 1,15,000 → Increase = 15% → Original price = 1,15,000 ÷ 1.15 = 1,00,000

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Part 7: Challenge (Optional)

31. SP = 900, Discount = 10% → MP = SP ÷ (1 – 0.1) = 900 ÷ 0.9 = 1000
32. 30% of number = 60 → Number = 60 ÷ 0.3 = 200
33. Population increased by 12% → Current = 56,000 → Last year = 56,000 ÷ 1.12 = 50,000
34. CP = 500, Profit = 10%, Discount = 12% → SP = CP × (1+0.10) = 500 × 1.10 = 550 → MP = SP ÷ (1 – 0.12) = 550 ÷ 0.88 ≈ 625
35. Price increased from 400 → 460 → Increase = 60 → % Increase = (60/400)×100 = 15%