Class 11 Chemistry Notes
Chapter 7: Redox Reactions
1. What are Redox Reactions?
A redox reaction is a chemical reaction in which oxidation and reduction occur at the same time.
Example:2Mg+O2→2MgO
Here,
- Magnesium is oxidised.
- Oxygen is reduced.
2. Oxidation
Oxidation means any one of the following:
- Addition of oxygen
- Removal of hydrogen
- Addition of an electronegative element
- Removal of an electropositive element
- Loss of electrons
- Increase in oxidation number
Examples
Addition of oxygen2Mg+O2→2MgO
Loss of hydrogenH2S+Cl2→S+2HCl
3. Reduction
Reduction means:
- Removal of oxygen
- Addition of hydrogen
- Removal of an electronegative element
- Addition of an electropositive element
- Gain of electrons
- Decrease in oxidation number
ExampleCuO+H2→Cu+H2O
Copper oxide loses oxygen, so it is reduced.
4. Electron Transfer Concept
Oxidation
Loss of electrons
ExampleNa→Na++e−
Reduction
Gain of electrons
ExampleCl2+2e−→2Cl−
5. Oxidising Agent
An oxidising agent
- Accepts electrons
- Causes oxidation of another substance
- Gets reduced itself
Examples
- Oxygen
- Chlorine
- Potassium permanganate
- Potassium dichromate
6. Reducing Agent
A reducing agent
- Donates electrons
- Causes reduction of another substance
- Gets oxidised itself
Examples
- Hydrogen
- Carbon
- Zinc
- Magnesium
7. Oxidation Number
Oxidation number is the imaginary charge assigned to an atom in a compound assuming complete transfer of electrons.
It helps identify oxidation and reduction.
8. Rules for Oxidation Number
Rule 1
Elements in free state = 0
Examples
- H₂
- O₂
- Cl₂
- Na
Rule 2
Simple ion
Oxidation number = Ionic charge
Examples
Na⁺ = +1
Mg²⁺ = +2
Cl⁻ = –1
Rule 3
Oxygen
Usually = −2
Exceptions
- Peroxides = −1
- Superoxides = −½
- OF₂ = +2
Rule 4
Hydrogen
Usually = +1
Metal hydrides = −1
Examples
NaH
CaH₂
Rule 5
Fluorine
Always = −1
Rule 6
Sum of oxidation numbers
Neutral compound = 0
Polyatomic ion = Charge on ion
9. Oxidation Number Examples
CO₂
Oxygen = −2
Let carbon = x
x + 2(−2)=0
x=+4
Carbon = +4
H₂SO₄
Hydrogen = +1
Oxygen = −2
Let sulphur = x
2(+1)+x+4(−2)=0
x=+6
Sulphur = +6
10. Oxidation and Reduction Using Oxidation Number
Increase in oxidation number
→ Oxidation
Decrease in oxidation number
→ Reduction
11. Types of Redox Reactions
A. Combination Reaction
Two or more substances combine to form one product.
Example2Mg+O2→2MgO
B. Decomposition Reaction
One compound breaks into simpler substances.
Example2KClO3→2KCl+3O2
C. Displacement Reaction
One element replaces another.
ExampleZn+CuSO4→ZnSO4+Cu
D. Disproportionation Reaction
The same element undergoes both oxidation and reduction.
Example2H2O2→2H2O+O2
Oxygen is both oxidised and reduced.
12. Balancing Redox Reactions
Two methods
- Oxidation Number Method
- Half Reaction Method
13. Important Differences
| Oxidation | Reduction |
|---|---|
| Loss of electrons | Gain of electrons |
| Increase in oxidation number | Decrease in oxidation number |
| Addition of oxygen | Removal of oxygen |
| Removal of hydrogen | Addition of hydrogen |
14. Quick Revision Table
| Term | Meaning |
|---|---|
| Oxidation | Loss of electrons |
| Reduction | Gain of electrons |
| Oxidising agent | Electron acceptor |
| Reducing agent | Electron donor |
| Oxidation Number | Imaginary charge on an atom |
| Redox Reaction | Oxidation and reduction together |
15. Important Exam Questions
- Define oxidation and reduction.
- What is a redox reaction?
- Define oxidising and reducing agents.
- State the rules for assigning oxidation numbers.
- Find the oxidation number of sulphur in H₂SO₄.
- Explain disproportionation reaction with one example.
- Differentiate oxidation and reduction.
- Explain oxidation in terms of electron transfer.
- Explain the oxidation number method.
- Classify different types of redox reactions.
1. Multiple Choice Questions (MCQs)
Basic MCQs
- Oxidation is the process of:
a) Gain of electrons
b) Loss of electrons
c) Gain of neutrons
d) Gain of protons - Reduction involves:
a) Increase in oxidation number
b) Gain of electrons
c) Addition of oxygen
d) Removal of hydrogen - Which of the following is always an oxidising agent?
a) Electron donor
b) Electron acceptor
c) Proton donor
d) Hydrogen donor - Which of the following is always reduced?
a) Oxidising agent
b) Reducing agent
c) Catalyst
d) Solvent - In Mg + Cl₂ → MgCl₂, magnesium is:
a) Reduced
b) Oxidised
c) Catalyst
d) Neutral - Which element always has oxidation number –1?
a) Oxygen
b) Chlorine
c) Fluorine
d) Hydrogen - Oxidation number of oxygen in H₂O₂ is:
a) –2
b) –1
c) +2
d) 0 - Oxidation number of hydrogen in NaH is:
a) +1
b) –1
c) 0
d) +2 - Which is a disproportionation reaction?
a) Zn + CuSO₄
b) 2H₂O₂ → 2H₂O + O₂
c) Mg + O₂
d) CaCO₃ → CaO + CO₂ - Which reaction is not a redox reaction?
a) Zn + CuSO₄
b) H₂ + Cl₂
c) CaCO₃ → CaO + CO₂
d) Fe₂O₃ + Al
2. Assertion–Reason Questions
Assertion: Oxidation and reduction always occur together.
Reason: Electron lost by one species is gained by another.
Assertion: Oxygen always has oxidation number –2.
Reason: Oxygen forms peroxides.
Assertion: Fluorine never shows positive oxidation state.
Reason: Fluorine is the most electronegative element.
Assertion: Oxidising agents gain electrons.
Reason: They themselves undergo reduction.
Assertion: Hydrogen peroxide is both an oxidising and reducing agent.
Reason: Oxygen in H₂O₂ has oxidation number –1.
3. Fill in the Blanks
- Oxidation is the ________ of electrons.
- Reduction is the ________ of electrons.
- Oxidising agent always ________ electrons.
- Reducing agent always ________ electrons.
- Oxidation number of elemental oxygen is ________.
- Oxidation number of fluorine is always ________.
- Hydrogen shows oxidation number ________ in metal hydrides.
- Oxidation number of oxygen in OF₂ is ________.
- Redox reactions involve simultaneous ________ and ________.
- Increase in oxidation number indicates ________.
- Decrease in oxidation number indicates ________.
- Potassium permanganate is a strong ________ agent.
- Zinc is a good ________ agent.
- Oxidation number of sulphur in H₂SO₄ is ________.
- Oxidation number of carbon in CO₂ is ________.
4. True or False
- Oxidation means gain of electrons.
- Reduction means gain of electrons.
- Oxygen always has oxidation number –2.
- Fluorine always has oxidation number –1.
- Hydrogen peroxide is a peroxide.
- Oxidation number of free elements is zero.
- Oxidation number of Na⁺ is +1.
- Oxidising agents donate electrons.
- Reduction decreases oxidation number.
- All decomposition reactions are redox reactions.
5. Match the Following
| Column A | Column B |
|---|---|
| Oxidation | Loss of electrons |
| Reduction | Gain of electrons |
| Oxidising agent | Electron acceptor |
| Reducing agent | Electron donor |
| Disproportionation | Same element oxidised and reduced |
6. Very Short Answer Questions (1 Mark)
- Define oxidation.
- Define reduction.
- What is oxidation number?
- What is an oxidising agent?
- What is a reducing agent?
- Define redox reaction.
- Give one example of oxidation.
- Give one example of reduction.
- Name one oxidising agent.
- Name one reducing agent.
7. Short Answer Questions (2–3 Marks)
- Explain oxidation in terms of electron transfer.
- Explain reduction using oxidation number.
- Write any four rules for oxidation number.
- Differentiate oxidising and reducing agents.
- Explain disproportionation reaction with an example.
- Explain combination redox reactions.
- Explain decomposition redox reactions.
- Explain displacement reactions.
- Why do oxidation and reduction always occur together?
- Explain electron transfer in NaCl formation.
8. Long Answer Questions (5 Marks)
- Explain oxidation number with all rules and suitable examples.
- Explain different types of redox reactions.
- Describe oxidation and reduction according to:
- Classical concept
- Electron transfer concept
- Oxidation number concept
- Explain balancing of redox reactions by oxidation number method.
- Explain balancing of redox reactions by half reaction method.
9. Numerical / Oxidation Number Questions
Find oxidation number of the indicated element in:
- H₂SO₄
- KMnO₄
- K₂Cr₂O₇
- Na₂S₂O₃
- NH₄Cl
- HNO₃
- HClO₄
- Fe₂O₃
- MnO₂
- Cu₂O
- ClO₃⁻
- SO₄²⁻
- Cr₂O₇²⁻
- CO₃²⁻
- H₂O₂
- OF₂
- KO₂
- Na₂O₂
- KClO₃
- H₃PO₄
10. Identify the Type of Redox Reaction
Classify each as:
- Combination
- Decomposition
- Displacement
- Disproportionation
- 2Mg + O₂ → 2MgO
- 2KClO₃ → 2KCl + 3O₂
- Zn + CuSO₄ → ZnSO₄ + Cu
- 2H₂O₂ → 2H₂O + O₂
- Cl₂ + 2OH⁻ → Cl⁻ + ClO⁻ + H₂O
11. Identify the Oxidising and Reducing Agents
For each reaction:
- Zn + CuSO₄ → ZnSO₄ + Cu
- Mg + O₂ → MgO
- Fe₂O₃ + Al → Al₂O₃ + Fe
- H₂ + Cl₂ → HCl
- CuO + H₂ → Cu + H₂O
12. HOTS (Higher Order Thinking Questions)
- Why can hydrogen peroxide act as both an oxidising and a reducing agent?
- Why does fluorine never undergo disproportionation?
- Why are oxidation numbers sometimes fractional?
- Why are redox reactions called electron-transfer reactions?
- Explain why NaH is considered a reducing agent.
13. Case-Based Questions
Case Study 1
A student places a zinc strip in copper sulphate solution. After some time, the blue colour fades and reddish-brown copper deposits on the zinc strip.
Answer:
- Which metal is oxidised?
- Which ion is reduced?
- Name the oxidising agent.
- Name the reducing agent.
- Write the balanced reaction.
Case Study 2
Hydrogen peroxide decomposes into water and oxygen.
Answer:
- Name the type of reaction.
- Find oxidation number of oxygen in H₂O₂.
- Which oxygen atoms are oxidised?
- Which oxygen atoms are reduced?
- Why is H₂O₂ unique?
14. One-Word Questions
- Electron donor = ________
- Electron acceptor = ________
- Increase in oxidation number = ________
- Decrease in oxidation number = ________
- Oxygen in peroxide = ________
- Oxygen in superoxide = ________
- Hydrogen in NaH = ________
- Oxidation number of free element = ________