Mock Test – JEE Main – Physics- Electrostatics

Q1.

Two point charges of 3 μC and 6 μC are 2 m apart. The force between them is:

A) 9 N
B) 4.5 N
C) 27 N
D) 12 N


Q2.

Coulomb’s law constant k=9×109N\cdotpm²/C²k = 9 \times 10^9 \, \text{N·m²/C²}k=9×109N\cdotpm²/C² appears in formula:

A) F=kq1q2r2F = \frac{k q_1 q_2}{r^2}F=r2kq1​q2​​
B) E=kqr2E = k q r^2E=kqr2
C) V=q4πϵ0r2V = \frac{q}{4\pi \epsilon_0 r^2}V=4πϵ0​r2q​
D) F=kq1q2r2F = k q_1 q_2 r^2F=kq1​q2​r2


Q3.

Electric field at the midpoint of two equal charges +Q separated by distance 2a:

A) Zero
B) Along the line joining charges
C) Perpendicular to the line joining charges
D) Cannot be determined


Q4.

Electric dipole moment is defined as:

A) qdqdqd
B) qd\frac{q}{d}dq​
C) dq\frac{d}{q}qd​
D) q2dq^2 dq2d


Q5.

Potential energy of a system of two charges q1 and q2 separated by distance r:

A) kq1q2r\frac{k q_1 q_2}{r}rkq1​q2​​
B) kq1q2rk q_1 q_2 rkq1​q2​r
C) kq1q22r\frac{k q_1 q_2}{2r}2rkq1​q2​​
D) kq1q2r2k q_1 q_2 r^2kq1​q2​r2


Q6.

Electric field at the center of a uniformly charged ring of radius R and total charge Q:

A) kQR2\frac{kQ}{R^2}R2kQ​
B) Zero
C) kQ2R2\frac{kQ}{2R^2}2R2kQ​
D) Infinite


Q7.

Force on a small charge q placed at a distance r from an infinite uniformly charged plane (charge density σ):

A) σ2ϵ0\frac{\sigma}{2 \epsilon_0}2ϵ0​σ​
B) σq2ϵ0\frac{\sigma q}{2 \epsilon_0}2ϵ0​σq​
C) σqϵ0r2\frac{\sigma q}{\epsilon_0 r^2}ϵ0​r2σq​
D) Zero


Q8.

Gauss’s law relates:

A) Electric flux to charge enclosed
B) Electric field to potential
C) Potential energy to charge
D) Electric flux to energy


Q9.

Two charges +q and –q separated by distance 2a: net electric field at midpoint is:

A) Zero
B) kqa2\frac{kq}{a^2}a2kq​ along dipole axis
C) kq2a2\frac{kq}{2a^2}2a2kq​ perpendicular
D) Infinite


Q10.

Potential at a point on the axis of a dipole at distance r from center (r >> a):

A) kpr2\frac{k p}{r^2}r2kp​
B) kpr3\frac{k p}{r^3}r3kp​
C) kqr\frac{k q}{r}rkq​
D) kpr2k p r^2kpr2


Q11.

Work done in moving a charge q from point A to B in an electric field depends on:

A) Only the points A and B
B) Path taken
C) Velocity of charge
D) Acceleration of charge


Q12.

Capacitance of a parallel plate capacitor depends on:

A) Area of plates and separation
B) Charge and voltage
C) Dielectric only
D) Temperature


Q13.

Energy stored in a capacitor:

A) 12CV2\frac{1}{2} C V^221​CV2
B) CV2C V^2CV2
C) 12V2/C\frac{1}{2} V^2/C21​V2/C
D) CVCVCV


Q14.

Two capacitors C1 and C2 in series. Equivalent capacitance:

A) C1+C2C_1 + C_2C1​+C2​
B) C1C2C1+C2\frac{C_1 C_2}{C_1 + C_2}C1​+C2​C1​C2​​
C) C1C2C_1 C_2C1​C2​
D) C1C2\sqrt{C_1 C_2}C1​C2​​


Q15.

Force between two point charges in vacuum is 10 N. If medium with dielectric constant 5 is inserted:

A) 2 N
B) 50 N
C) 10 N
D) 5 N


Q16.

Electric field inside a conductor in electrostatic equilibrium:

A) Maximum at surface
B) Zero
C) Same everywhere
D) Depends on shape


Q17.

Two point charges of opposite sign are separated by distance r. Potential at midpoint:

A) Zero
B) Maximum
C) Minimum
D) Infinite


Q18.

Electric field due to an infinite uniformly charged plane:

A) Varies with distance
B) Constant, independent of distance
C) Zero
D) Infinite


Q19.

Dipole placed in uniform electric field experiences:

A) Net force only
B) Net torque only
C) Both force and torque
D) Neither


Q20.

Potential at a point due to a point charge q:

A) kqr2\frac{kq}{r^2}r2kq​
B) kqr\frac{kq}{r}rkq​
C) kqrkqrkqr
D) kqr2kq r^2kqr2


Q21.

Unit of electric flux in SI:

A) N·m²/C
B) N/C
C) C/N·m²
D) V·m


Q22.

If distance between two charges doubles, force between them:

A) Doubles
B) Halves
C) Quarter
D) Quadruples


Q23.

For a parallel plate capacitor in vacuum, inserting a dielectric:

A) Increases capacitance
B) Decreases capacitance
C) Leaves capacitance same
D) Depends on voltage


Q24.

Electrostatic potential energy of a system of two charges q1 and q2 separated by r:

A) kq1q2r\frac{k q_1 q_2}{r}rkq1​q2​​
B) kq1q2rk q_1 q_2 rkq1​q2​r
C) kq1q2r2k q_1 q_2 r^2kq1​q2​r2
D) kq1q22r2\frac{k q_1 q_2}{2r^2}2r2kq1​q2​​


Q25.

Work done in moving a charge along an equipotential surface:

A) Maximum
B) Zero
C) Depends on path
D) Depends on charge

Answer

Question No.Answer
1B
2A
3A
4A
5A
6B
7B
8A
9B
10B
11A
12A
13A
14B
15A
16B
17A
18B
19B
20B
21A
22C
23A
24A
25B

Solution

ELECTROSTATICS – DETAILED SOLUTIONS


Q1. Force between two charges

F=kq1q2r2=9×1093×1066×10622=4.5NF = k \frac{q_1 q_2}{r^2} = 9 \times 10^9 \frac{3 \times 10^{-6} \cdot 6 \times 10^{-6}}{2^2} = 4.5\,\text{N}F=kr2q1​q2​​=9×109223×10−6⋅6×10−6​=4.5N

Answer: B


Q2. Coulomb’s law constant

Formula: F=kq1q2r2F = k \frac{q_1 q_2}{r^2}F=kr2q1​q2​​

Answer: A


Q3. Electric field at midpoint of two equal charges +Q

  • Fields due to each charge point away from charge
  • At midpoint, they cancel → net field = 0

Answer: A


Q4. Electric dipole moment

p=qdp = q \cdot dp=q⋅d

Answer: A


Q5. Potential energy of two charges

U=kq1q2rU = k \frac{q_1 q_2}{r}U=krq1​q2​​

Answer: A


Q6. Electric field at center of a uniformly charged ring

  • Symmetry → all components cancel at the center → E = 0

Answer: B


Q7. Force on charge near infinite plane

E=σ2ϵ0    F=qE=σq2ϵ0E = \frac{\sigma}{2 \epsilon_0} \implies F = q E = \frac{\sigma q}{2 \epsilon_0}E=2ϵ0​σ​⟹F=qE=2ϵ0​σq​

Answer: B


Q8. Gauss’s law

ΦE=Qenclosedϵ0\Phi_E = \frac{Q_\text{enclosed}}{\epsilon_0}ΦE​=ϵ0​Qenclosed​​

Answer: A


Q9. Electric field at midpoint of dipole (+q, –q)

  • Equal magnitude but opposite direction along dipole axis → net field: E=kqa2E = \frac{kq}{a^2}E=a2kq​ along axis

Answer: B


Q10. Potential on axis of dipole at distance r (r >> a)

V=kpr2(approximate, far from dipole)V = \frac{k p}{r^2} \quad \text{(approximate, far from dipole)}V=r2kp​(approximate, far from dipole)

Answer: B


Q11. Work done moving a charge in an electric field

  • Electric field is conservative → depends only on start and end points

Answer: A


Q12. Capacitance of parallel plate capacitor

C=ϵ0AdC = \frac{\epsilon_0 A}{d}C=dϵ0​A​

Depends on area A and separation d

Answer: A


Q13. Energy stored in a capacitor

U=12CV2U = \frac{1}{2} C V^2U=21​CV2

Answer: A


Q14. Capacitors in series

1Ceq=1C1+1C2    Ceq=C1C2C1+C2\frac{1}{C_\text{eq}} = \frac{1}{C_1} + \frac{1}{C_2} \implies C_\text{eq} = \frac{C_1 C_2}{C_1 + C_2}Ceq​1​=C1​1​+C2​1​⟹Ceq​=C1​+C2​C1​C2​​

Answer: B


Q15. Force with dielectric medium

  • Force decreases by factor of dielectric constant KKK:

Fnew=FK=105=2NF_\text{new} = \frac{F}{K} = \frac{10}{5} = 2\,\text{N}Fnew​=KF​=510​=2N

Answer: A


Q16. Electric field inside a conductor

  • At electrostatic equilibrium, E = 0

Answer: B


Q17. Potential at midpoint between opposite charges

  • Potentials of +q and –q cancel → V = 0

Answer: A


Q18. Electric field due to infinite plane

  • Constant everywhere, independent of distance:

E=σ2ϵ0E = \frac{\sigma}{2 \epsilon_0}E=2ϵ0​σ​

Answer: B


Q19. Dipole in uniform electric field

  • Experiences torque but no net force

Answer: B


Q20. Potential due to point charge

V=kqrV = k \frac{q}{r}V=krq​

Answer: B


Q21. Unit of electric flux

ΦE=EA    N\cdotpm²/C\Phi_E = E \cdot A \implies \text{N·m²/C}ΦE​=E⋅A⟹N\cdotpm²/C

Answer: A


Q22. Force vs distance

  • Coulomb’s law: F1r2F \propto \frac{1}{r^2}F∝r21​
  • Distance doubles → FF/4F \to F/4F→F/4

Answer: C


Q23. Dielectric in parallel plate capacitor

  • Capacitance increases by factor of dielectric constant

Answer: A


Q24. Electrostatic potential energy

U=kq1q2rU = k \frac{q_1 q_2}{r}U=krq1​q2​​

Answer: A


Q25. Work along equipotential surface

  • No change in potential → work done = 0

Answer: B