Amines – MCQs (NEET Style)
Q1. The functional group of amines is:
A. –OH
B. –NH₂
C. –COOH
D. –C=O
Q2. Which of the following is a primary amine?
A. CH₃NH₂
B. (CH₃)₂NH
C. (CH₃)₃N
D. C₆H₅NHCH₃
Q3. Which of the following is a secondary amine?
A. CH₃NH₂
B. (CH₃)₂NH
C. (CH₃)₃N
D. C₆H₅NH₂
Q4. Which of the following is a tertiary amine?
A. CH₃NH₂
B. (CH₃)₂NH
C. (CH₃)₃N
D. C₆H₅NHCH₃
Q5. Aromatic amine example:
A. CH₃NH₂
B. C₆H₅NH₂
C. (CH₃)₂NH
D. (CH₃)₃N
Q6. Amines are classified as:
A. Primary, secondary, tertiary
B. Aliphatic, aromatic
C. Both A and B
D. Only aliphatic
Q7. The IUPAC name of CH₃NH₂ is:
A. Methylamine
B. Aminomethane
C. Methanamine
D. Both B and C
Q8. Amines have:
A. Lone pair of electrons on N
B. sp³ hybridization of N
C. Basic character
D. All of the above
Q9. Which amine is most basic?
A. Methylamine
B. Aniline
C. Diethylamine
D. Trimethylamine
Q10. The order of basicity in aqueous solution:
A. Secondary > Primary > Tertiary > Aromatic
B. Tertiary > Secondary > Primary > Aromatic
C. Aromatic > Primary > Secondary > Tertiary
D. Primary > Secondary > Tertiary > Aromatic
Q11. Amines can be prepared by:
A. Reduction of nitriles
B. Gabriel phthalimide synthesis
C. Hoffmann bromamide degradation
D. All of the above
Q12. Reductive amination is:
A. Aldehyde/ketone + Ammonia/amine + Reducing agent → Amine
B. Amine + Acid → Salt
C. Amine + SOCl₂ → Alkyl halide
D. None of the above
Q13. Reaction of amine with HCl produces:
A. Amine hydrochloride
B. Amide
C. Ether
D. Alcohol
Q14. Primary amine + NaNO₂ + HCl (0–5°C) →
A. Diazonium salt
B. Alcohol
C. Ketone
D. Aldehyde
Q15. Secondary amine + NaNO₂ + HCl →
A. N-nitrosoamine
B. Diazonium salt
C. Alcohol
D. Ether
Q16. Tertiary amine + HNO₂ →
A. No reaction
B. N-nitrosoamine
C. Diazonium salt
D. Alcohol
Q17. Nucleophilicity of amines:
A. Aliphatic > Aromatic
B. Aromatic > Aliphatic
C. Equal
D. None of the above
Q18. Aniline + Bromine water →
A. 2,4,6-tribromoaniline
B. Monobromoaniline
C. No reaction
D. Nitroaniline
Q19. Aniline + HNO₂ at 0–5°C →
A. Benzenediazonium chloride
B. N-nitrosoaniline
C. Nitrobenzene
D. Bromobenzene
Q20. Hoffmann bromamide reaction converts:
A. Primary amide → Primary amine
B. Secondary amide → Secondary amine
C. Both A and B
D. Ketone → Amine
Q21. Order of basicity in gas phase:
A. Tertiary > Secondary > Primary > Aromatic
B. Primary > Secondary > Tertiary > Aromatic
C. Aromatic > Primary > Secondary > Tertiary
D. Secondary > Tertiary > Primary > Aromatic
Q22. Amines + acyl chloride →
A. Amide
B. Ester
C. Alkyl halide
D. Alcohol
Q23. Amines + acid anhydride →
A. Amide
B. Ester
C. Alcohol
D. Ketone
Q24. Amines react with nitrous acid to:
A. Form diazonium salts (primary aromatic)
B. Form N-nitrosoamine (secondary)
C. No reaction (tertiary)
D. All of the above
Q25. Primary amine + CH₃COCl →
A. N-methylacetamide
B. Acetamide
C. Secondary amine
D. Tertiary amine
Q26. Aliphatic amines + HNO₂ →
A. Alcohol (via diazonium intermediate)
B. N-nitrosoamine
C. Ketone
D. Aldehyde
Q27. Aromatic amine + NaNO₂/HCl (0–5°C) →
A. Diazonium salt
B. Alcohol
C. Ether
D. Aldehyde
Q28. Amines + CO₂ + H₂O →
A. Ammonium carbamate formation
B. Amide
C. Carbocation
D. Alcohol
Q29. Aniline + CH₃COCl →
A. Acetanilide
B. Acetamide
C. N-methyl aniline
D. N,N-dimethyl aniline
Q30. Amines are soluble in water due to:
A. Hydrogen bonding
B. Ionic bonding
C. Van der Waals forces
D. None
Q31. Amines react with nitrous acid at 0–5°C to give:
A. Aliphatic primary → Alcohol
B. Aromatic primary → Diazonium salt
C. Secondary → N-nitrosoamine
D. All of the above
Q32. Which amine shows strongest nucleophilicity?
A. Aliphatic secondary
B. Aliphatic primary
C. Aromatic
D. Tertiary
Q33. Methylamine + CH₃COCl →
A. N-methylacetamide
B. Acetamide
C. Alcohol
D. Ketone
Q34. Aromatic amines + Br₂ →
A. 2,4,6-tribromoaniline
B. Monobromoaniline
C. No reaction
D. Nitroaniline
Q35. Aniline + HNO₃ + H₂SO₄ →
A. Nitroaniline
B. Dinitroaniline
C. No reaction
D. Bromaniline
Q36. Amines + SOCl₂ →
A. Alkyl halide
B. Alcohol
C. Amide
D. Ketone
Q37. Aniline + HCl →
A. Anilinium chloride (salt formation)
B. Amide
C. Alcohol
D. Ketone
Q38. Amines are basic because:
A. Lone pair on nitrogen can accept H⁺
B. Lone pair on carbon can accept H⁺
C. π electrons
D. None
Q39. Tertiary amines + HCl →
A. Salt formation only
B. Amide
C. No reaction
D. Alcohol
Q40. Aromatic amines are less basic than aliphatic amines because:
A. Lone pair delocalized into benzene ring
B. Steric hindrance
C. Resonance with halogen
D. None
Q41. Hoffmann bromamide reaction involves:
A. Br₂ + NaOH + Amide → Amine
B. HNO₃ + Amide → Amine
C. SOCl₂ + Amide → Amine
D. LiAlH₄ + Amide → Alcohol
Q42. Gabriel phthalimide synthesis produces:
A. Primary amines
B. Secondary amines
C. Tertiary amines
D. Alcohols
Q43. Reduction of nitrobenzene →
A. Aniline
B. Phenol
C. Nitroaniline
D. Benzylamine
Q44. Amines + formaldehyde + HCl →
A. Mannich base
B. Schiff base
C. Amide
D. Alcohol
Q45. Amines react with COCl₂ (phosgene) →
A. Urea derivative
B. Amide
C. Ester
D. Alcohol
Q46. Aromatic amine + HONO →
A. Diazonium salt
B. Alcohol
C. Ketone
D. N-nitrosoamine
Q47. Secondary aromatic amines + HONO →
A. N-nitrosoamine
B. Diazonium salt
C. Alcohol
D. Ether
Q48. Amines + conc. H₂SO₄ (hot) →
A. Protonated amine
B. Alkylation
C. Oxidation
D. Sulfonation
Q49. Amines are used in:
A. Dyes
B. Pharmaceuticals
C. Intermediates in chemicals
D. All of the above
Q50. Which of the following is a tertiary aliphatic amine?
A. (CH₃)₃N
B. CH₃NH₂
C. (CH₃)₂NH
D. C₆H₅NH₂
Q1. B – Amines have –NH₂ functional group.
Q2. A – CH₃NH₂ is a primary amine (one alkyl group attached to N).
Q3. B – (CH₃)₂NH is a secondary amine (two alkyl groups attached to N).
Q4. C – (CH₃)₃N is a tertiary amine (three alkyl groups attached to N).
Q5. B – C₆H₅NH₂ is an aromatic amine (amine attached to benzene).
Q6. C – Amines are classified as primary, secondary, tertiary, and also aliphatic/aromatic.
Q7. D – CH₃NH₂ IUPAC name: Methanamine (or Aminomethane).
Q8. D – Amines have lone pair on N, sp³ hybridization, and show basicity.
Q9. C – Diethylamine is more basic than methylamine or aromatic amines.
Q10. A – In aqueous solution: Secondary > Primary > Tertiary > Aromatic (tertiary less soluble due to sterics).
Q11. D – Amines can be prepared by reduction of nitriles, Gabriel synthesis, Hoffmann degradation.
Q12. A – Reductive amination converts aldehyde/ketone to amine using ammonia/amine + reducing agent.
Q13. A – Amines react with acids to form salts (amine hydrochloride).
Q14. A – Primary amines + NaNO₂/HCl → Diazonium salts (0–5°C).
Q15. A – Secondary amines + HNO₂ → N-nitrosoamine.
Q16. A – Tertiary amines + HNO₂ → No reaction.
Q17. A – Aliphatic amines are more nucleophilic than aromatic amines.
Q18. A – Aniline + Br₂ → 2,4,6-tribromoaniline (electrophilic substitution).
Q19. A – Aniline + NaNO₂/HCl → Benzenediazonium chloride.
Q20. A – Hoffmann bromamide reaction: primary amide → primary amine.
Q21. A – Gas phase basicity: Tertiary > Secondary > Primary > Aromatic.
Q22. A – Amines react with acyl chlorides → Amides.
Q23. A – Amines react with acid anhydrides → Amides.
Q24. D – Amines react with nitrous acid differently: primary aromatic → diazonium, secondary → N-nitroso, tertiary → no reaction.
Q25. A – CH₃NH₂ + CH₃COCl → N-methylacetamide.
Q26. A – Aliphatic primary amines + HNO₂ → Alcohol via diazonium decomposition.
Q27. A – Aromatic primary amines + NaNO₂/HCl → Diazonium salt.
Q28. A – Amines + CO₂ + H₂O → Ammonium carbamate formation.
Q29. A – Aniline + CH₃COCl → Acetanilide (protects amine).
Q30. A – Amines are soluble in water due to hydrogen bonding.
Q31. D – Amines react with nitrous acid differently depending on type (aliphatic primary → alcohol, aromatic primary → diazonium, secondary → N-nitroso).
Q32. A – Aliphatic secondary amines are stronger nucleophiles than primary or aromatic.
Q33. A – Methylamine + CH₃COCl → N-methylacetamide.
Q34. A – Aromatic amines + Br₂ → 2,4,6-tribromoaniline.
Q35. B – Aniline + HNO₃/H₂SO₄ → Nitroaniline (electrophilic substitution).
Q36. A – Amines + SOCl₂ → Alkyl halide formation.
Q37. A – Aniline + HCl → Anilinium chloride (salt).
Q38. A – Amines are basic due to lone pair on N.
Q39. A – Tertiary amines + HCl → Salt formation only.
Q40. A – Aromatic amines are less basic because lone pair delocalized into benzene.
Q41. A – Hoffmann bromamide reaction: Br₂ + NaOH + Amide → Amine + CO₂.
Q42. A – Gabriel synthesis produces primary amines.
Q43. A – Reduction of nitrobenzene → Aniline.
Q44. A – Amines + formaldehyde + HCl → Mannich base.
Q45. A – Amines + COCl₂ (phosgene) → Urea derivatives.
Q46. A – Aromatic primary amines + HONO → Diazonium salts.
Q47. A – Secondary aromatic amines + HONO → N-nitrosoamine.
Q48. A – Amines + conc. H₂SO₄ → Protonation.
Q49. D – Amines are used in dyes, pharmaceuticals, intermediates.
Q50. A – (CH₃)₃N is tertiary aliphatic amine.
Disclaimer:
All MCQs and solutions are educational, and for practice purposes only. They are based on NCERT and NEET syllabus and are not official NEET questions.