2025
Q1. Derive the de Broglie wavelength of a particle moving with momentum p.
Q2. A photon of wavelength 400 nm strikes a metal surface with work function 2 eV. Calculate the maximum kinetic energy of the emitted photoelectron.
Q3. Explain the photoelectric effect and state the experimental observations that confirm the particle nature of light.
2024
Q1. Derive the expression for the energy of a photon in terms of its frequency.
Q2. Calculate the threshold frequency for a metal with work function 4.5 eV.
Q3. Explain why increasing the intensity of light does not increase the kinetic energy of photoelectrons.
2023
Q1. A particle has mass m and velocity v. Write the expression for its de Broglie wavelength and discuss the significance.
Q2. Explain Einstein’s photoelectric equation and its terms.
Q3. Discuss experimental verification of matter waves using electron diffraction.
2022
Q1. A photon of wavelength 250 nm falls on a surface with work function 3 eV. Calculate the stopping potential.
Q2. Derive the expression for de Broglie wavelength in terms of kinetic energy.
Q3. Explain the difference between wave and particle nature of light with suitable examples.
2021
Q1. Derive the expression for de Broglie wavelength for electrons accelerated through a potential difference V.
Q2. Explain the significance of the Davisson–Germer experiment in confirming the wave nature of electrons.
Q3. A photon of frequency f strikes a metal surface. Write the expression for the maximum velocity of emitted electrons.
2020
Q1. Explain the concept of matter waves and derive the de Broglie relation.
Q2. A metal surface has work function 2.5 eV. Light of wavelength 300 nm is incident. Find the maximum kinetic energy of photoelectrons.
Q3. Discuss the limitations of classical wave theory in explaining the photoelectric effect.
2019
Q1. Derive the relation between wavelength and momentum for a particle.
Q2. Explain the photoelectric effect with a suitable diagram.
Q3. An electron is accelerated through 100 V. Calculate its de Broglie wavelength.
2018
Q1. Derive the expression for photon energy in terms of wavelength.
Q2. Explain the stopping potential and its relation with kinetic energy of photoelectrons.
Q3. Explain how electron diffraction confirms the wave nature of matter.
2017
Q1. A photon of wavelength 500 nm falls on a metal surface (work function 2 eV). Find kinetic energy of photoelectron.
Q2. Write the expression for de Broglie wavelength of electron in terms of accelerating voltage.
Q3. Describe an experiment to demonstrate wave nature of electrons.
2016
Q1. Derive the energy–momentum relation for a photon.
Q2. A particle of mass m moves with velocity v. Find the corresponding de Broglie wavelength.
Q3. Explain why the classical theory fails to explain the photoelectric effect.
2015
Q1. Derive the de Broglie wavelength of a particle moving under a potential difference V.
Q2. Explain Einstein’s photoelectric equation.
Q3. Electron accelerated through 200 V → calculate its de Broglie wavelength.
2014
Q1. Derive the expression for the kinetic energy of photoelectrons in the photoelectric effect.
Q2. Explain the significance of the de Broglie hypothesis.
Q3. Describe an experiment that confirms wave nature of electrons.
2013
Q1. Photon of frequency f strikes a metal with work function φ. Derive expression for stopping potential.
Q2. Derive the de Broglie wavelength for a particle of mass m and kinetic energy K.
Q3. Discuss the dual nature of matter and radiation with examples.
Dual Nature of Matter and Radiation — Solutions (2025 → 2013)
2025
Q1. de Broglie wavelength:λ=phwhere p=momentum of particle, h=Planck’s constant
Q2. Photon λ = 400 nm, work function φ = 2 eV.Ephoton=λhc=400×10−96.626×10−34⋅3×108≈4.97×10−19J≈3.1eV
Maximum kinetic energy:Kmax=Ephoton−ϕ=3.1−2=1.1eV
Q3. Photoelectric effect observations:
- Instantaneous emission of electrons.
- KE depends on frequency, not intensity.
- Number of electrons depends on intensity.
Confirms particle nature of light (photons).
2024
Q1. Photon energy: E=hν, ν= frequency
Q2. Threshold frequency: f0=ϕ/h=4.5/4.136×10−15≈1.088×1015Hz
Q3. Increasing intensity increases number of electrons but not their kinetic energy, since KE depends on frequency.
2023
Q1. de Broglie wavelength: λ=h/p=h/(mv)
Q2. Einstein’s photoelectric equation: Kmax=hν−ϕ
Q3. Electron diffraction: Electrons diffracted by crystal lattice → interference pattern → confirms wave nature.
2022
Q1. Photon λ = 250 nm, φ = 3 eV:E=λhc=250×10−96.626×10−34⋅3×108≈7.95×10−19J≈4.97eV
Stopping potential:Kmax=eVs=E−ϕ=4.97−3=1.97eV⟹Vs=1.97V
Q2. de Broglie wavelength in terms of kinetic energy:λ=ph=2mKh
Q3. Wave nature: diffraction/interference, particle nature: photoelectric effect.
2021
Q1. Electron accelerated through V:λ=ph=2meVh
Q2. Davisson–Germer experiment: electrons diffracted by crystal → wave behavior confirmed.
Q3. Photon incident → max velocity of photoelectron:Kmax=21mvmax2=hν−ϕ⟹vmax=m2(hν−ϕ)
2020
Q1. Matter waves: λ=h/p, significance: particles show wave behavior at atomic scale.
Q2. λ = 300 nm, φ = 2.5 eV → E = 4.14 eV → Kmax = 4.14 – 2.5 = 1.64 eV
Q3. Classical wave theory predicts KE ∝ intensity, cannot explain threshold frequency → quantum theory needed.
2019
Q1. Wavelength-momentum relation: λ=h/p
Q2. Photoelectric effect diagram: light → metal → emitted electrons → stopping potential measurement.
Q3. Electron accelerated through V = 100 V:p=2meV,λ=ph=2meVh≈1.23×10−10m
2018
Q1. Photon energy in terms of wavelength: E=hc/λ
Q2. Stopping potential: Vs=Kmax/e=(hν−ϕ)/e
Q3. Electron diffraction → wave nature confirmed via interference pattern.
2017
Q1. λ = 500 nm photon, φ = 2 eV → E = 2.48 eV → Kmax = 0.48 eV
Q2. de Broglie wavelength for electron accelerated through V:λ=2meVh
Q3. Experiment: electron diffraction by crystal → observed interference → wave nature.
2016
Q1. Photon energy-momentum relation: E=pc
Q2. Particle mass m, velocity v → λ=h/(mv)
Q3. Classical theory fails: cannot explain threshold frequency, instantaneous emission → quantum theory needed.
2015
Q1. Electron accelerated through V → λ=h/2meV
Q2. Einstein’s photoelectric equation: Kmax=hν−ϕ
Q3. V = 200 V → λ=h/2meV≈8.6×10−12m
2014
Q1. Photoelectron KE: Kmax=hν−ϕ
Q2. de Broglie hypothesis: particles can show wave behavior → λ=h/p
Q3. Electron diffraction confirms wave behavior of matter.
2013
Q1. Stopping potential:eVs=Kmax=hν−ϕ⟹Vs=ehν−ϕ
Q2. de Broglie wavelength:λ=2mKh
Q3. Dual nature:
- Light → wave: interference, diffraction; particle: photoelectric effect
- Matter → particle: mass, momentum; wave: electron diffraction, de Broglie wavelength