Class 10 Maths Introduction to Trigonometry MCQs

Class 10 Mathematics — Chapter 8

Introduction to Trigonometry: Question Bank


A. Multiple Choice Questions (MCQs)

1. In a right-angled triangle, the side opposite the right angle is called the:

A. Adjacent side
B. Opposite side
C. Hypotenuse
D. Base

2. For an acute angle AA,sinA=\sin A=

A. AdjacentHypotenuse\frac{\text{Adjacent}}{\text{Hypotenuse}}
B. OppositeHypotenuse\frac{\text{Opposite}}{\text{Hypotenuse}}
C. HypotenuseOpposite\frac{\text{Hypotenuse}}{\text{Opposite}}
D. OppositeAdjacent\frac{\text{Opposite}}{\text{Adjacent}}

3. Which of the following is the reciprocal of cosA\cos A?

A. cosecA\cosec A
B. cotA\cot A
C. secA\sec A
D. tanA\tan A

4. Which relation is correct?

A. tanA=cosAsinA\tan A=\frac{\cos A}{\sin A}
B. tanA=sinAcosA\tan A=\sin A\cos A
C. tanA=sinAcosA\tan A=\frac{\sin A}{\cos A}
D. tanA=1sinA\tan A=\frac1{\sin A}

5. If tanA=43\tan A=\frac43, then the corresponding sides opposite and adjacent to AA can be taken as:

A. 3k,4k3k,4k
B. 4k,3k4k,3k
C. 4k,5k4k,5k
D. 3k,5k3k,5k

6. If the opposite and adjacent sides of an acute angle are 55 and 1212, respectively, its hypotenuse is:

A. 7
B. 13
C. 17
D. 60

7. The value of sin45\sin45^\circ is:

A. 11
B. 12\frac12
C. 12\frac1{\sqrt2}
D. 3\sqrt3

8. The value of tan60\tan60^\circ is:

A. 13\frac1{\sqrt3}
B. 11
C. 12\frac12
D. 3\sqrt3

9. Which of the following is not defined?

A. sin90\sin90^\circ
B. cos0\cos0^\circ
C. tan90\tan90^\circ
D. cot90\cot90^\circ

10. The value of cos60\cos60^\circ is:

A. 00
B. 12\frac12
C. 32\frac{\sqrt3}{2}
D. 11

11. If sinA=35\sin A=\frac35, then cosA\cos A, for an acute angle AA, is:

A. 34\frac34
B. 45\frac45
C. 54\frac54
D. 25\frac25

12. If cotA=74\cot A=\frac74, then tanA\tan A is:

A. 74\frac74
B. 47\frac47
C. 37\frac37
D. 114\frac{11}{4}

13. Which identity is correct?

A. sin2Acos2A=1\sin^2A-\cos^2A=1
B. sin2A+cos2A=1\sin^2A+\cos^2A=1
C. sinA+cosA=1\sin A+\cos A=1
D. sin2A+tan2A=1\sin^2A+\tan^2A=1

14. From 1+tan2A=sec2A1+\tan^2A=\sec^2A, we get:

A. sec2A+tan2A=1\sec^2A+\tan^2A=1
B. sec2Atan2A=1\sec^2A-\tan^2A=1
C. tan2Asec2A=1\tan^2A-\sec^2A=1
D. secAtanA=1\sec A-\tan A=1

15. Which identity is valid?

A. cosec2A+cot2A=1\cosec^2A+\cot^2A=1
B. cosec2Acot2A=1\cosec^2A-\cot^2A=1
C. cot2Acosec2A=1\cot^2A-\cosec^2A=1
D. cosecAcotA=1\cosec A-\cot A=1

16. As an acute angle increases from 00^\circ to 9090^\circ:

A. sinA\sin A decreases
B. cosA\cos A increases
C. sinA\sin A increases and cosA\cos A decreases
D. Both remain constant

17. If sinA=sinB\sin A=\sin B, where AA and BB are acute angles, then:

A. A+B=90A+B=90^\circ
B. A=BA=B
C. AB=90A-B=90^\circ
D. A=2BA=2B

18. If tanA=1\tan A=1, then AA, being acute, is:

A. 3030^\circ
B. 4545^\circ
C. 6060^\circ
D. 9090^\circ

19. If secA=2\sec A=2, then cosA\cos A is:

A. 22
B. 12\frac12
C. 3\sqrt3
D. 11

20. Which ratio is always greater than or equal to 11 in its defined acute-angle range?

A. sinA\sin A
B. cosA\cos A
C. secA\sec A
D. tanA\tan A


B. Fill in the Blanks

21. Trigonometry studies the relationship between the ______ and ______ of a triangle.

22. The longest side of a right triangle is called the ______.

23.sinA=______hypotenuse\sin A=\frac{\_\_\_\_\_\_}{\text{hypotenuse}}

24.cosA=adjacent side______\cos A=\frac{\text{adjacent side}}{\_\_\_\_\_\_}

25.tanA=______adjacent side\tan A=\frac{\_\_\_\_\_\_}{\text{adjacent side}}

26. cosecA\cosec A is the reciprocal of ______.

27. secA\sec A is the reciprocal of ______.

28. cotA\cot A is the reciprocal of ______.

29.tanA=______cosA\tan A=\frac{\_\_\_\_\_\_}{\cos A}

30.cotA=cosA______\cot A=\frac{\cos A}{\_\_\_\_\_\_}

31.sin0=______\sin0^\circ=\_\_\_\_\_\_

32.cos90=______\cos90^\circ=\_\_\_\_\_\_

33.tan45=______\tan45^\circ=\_\_\_\_\_\_

34.sin30=______\sin30^\circ=\_\_\_\_\_\_

35.cos60=______\cos60^\circ=\_\_\_\_\_\_

36.sin2A+cos2A=______\sin^2A+\cos^2A=\_\_\_\_\_\_

37.1+tan2A=______1+\tan^2A=\_\_\_\_\_\_

38.1+cot2A=______1+\cot^2A=\_\_\_\_\_\_

39. tan90\tan90^\circ is ______.

40. cosec0\cosec0^\circ is ______.


C. True or False

41. The value of sinA\sin A can be greater than 11.

42. The value of cosA\cos A can be greater than 11 for an acute angle.

43. secA\sec A is the reciprocal of cosA\cos A.

44. tanA=cosAsinA\tan A=\frac{\cos A}{\sin A}.

45. sin45=cos45\sin45^\circ=\cos45^\circ.

46. tan45=1\tan45^\circ=1.

47. tan90\tan90^\circ is defined.

48. cot0\cot0^\circ is not defined.

49.sin2A+cos2A=1\sin^2A+\cos^2A=1

is a trigonometric identity.

50. sinA\sin A decreases as AA increases from 00^\circ to 9090^\circ.

51. cosA\cos A decreases from 11 to 00 as AA increases from 00^\circ to 9090^\circ.

52. If two acute angles have equal sine values, the angles are equal.

53. cosecA=sin1A\cosec A=\sin^{-1}A.

54. tanA=sinAcosA\tan A=\frac{\sin A}{\cos A}.


D. Assertion–Reason Questions

Choose:

A. Both Assertion and Reason are true, and Reason correctly explains Assertion.
B. Both are true, but Reason does not correctly explain Assertion.
C. Assertion is true, Reason is false.
D. Assertion is false, Reason is true.

55. Assertion: sinA1\sin A\leq1 for an acute angle.
Reason: The hypotenuse is the longest side of a right triangle.

56. Assertion: tan90\tan90^\circ is not defined.
Reason: tanA=sinAcosA\tan A=\frac{\sin A}{\cos A}, and cos90=0\cos90^\circ=0.

57. Assertion: sin45=cos45\sin45^\circ=\cos45^\circ.
Reason: In a 45459045^\circ-45^\circ-90^\circ triangle, the two perpendicular sides are equal.

58. Assertion: secA1\sec A\geq1 for 0A<900^\circ\leq A<90^\circ.
Reason: secA\sec A is the reciprocal of cosA\cos A, whose value is at most 11 in this range.

59. Assertion: cot0=0\cot0^\circ=0.
Reason: cotA=cosAsinA\cot A=\frac{\cos A}{\sin A}.

60. Assertion: The trigonometric ratios of an angle do not change when the size of the similar right triangle changes.
Reason: Corresponding sides of similar triangles are proportional.


E. Very Short Answer Questions

61. Define trigonometry.

62. What is meant by the hypotenuse of a right triangle?

63. Write the reciprocal of tanA\tan A.

64. Write tanA\tan A in terms of sinA\sin A and cosA\cos A.

65. Write cotA\cot A in terms of sinA\sin A and cosA\cos A.

66. What is the value of sin90\sin90^\circ?

67. What is the value of cos0\cos0^\circ?

68. What is the value of tan45\tan45^\circ?

69. What is the value of cot90\cot90^\circ?

70. Name the three fundamental Pythagorean trigonometric identities given in the chapter.


F. Short Answer / Numerical Questions

71. If tanA=34\tan A=\frac34, find sinA\sin A and cosA\cos A.

72. If sinA=513\sin A=\frac5{13}, find cosA\cos A and tanA\tan A.

73. Given 15cotA=815\cot A=8, find sinA\sin A and secA\sec A.

74. Given secA=1312\sec A=\frac{13}{12}, find all the other trigonometric ratios of AA.

75. If cotA=78\cot A=\frac78, find tanA\tan A.

76. In a right triangle, the sides opposite and adjacent to an acute angle are 88 cm and 1515 cm. Find all six trigonometric ratios.

77. In a right triangle, hypotenuse =13=13 cm and one perpendicular side =5=5 cm. Find the six ratios corresponding to the angle opposite the 55 cm side.

78. If tanA=1\tan A=1, verify that:2sinAcosA=1.2\sin A\cos A=1.

79. Evaluate:sin60cos30+sin30cos60.\sin60^\circ\cos30^\circ+ \sin30^\circ\cos60^\circ.

80. Evaluate:2tan245+cos230sin260.2\tan^245^\circ+\cos^230^\circ-\sin^260^\circ.


G. Identity-Based Questions

81. Prove:sec2Atan2A=1.\sec^2A-\tan^2A=1.

82. Prove:cosec2Acot2A=1.\cosec^2A-\cot^2A=1.

83. If tanA=13\tan A=\frac1{\sqrt3}, find secA,cosA,sinA,cosecA,cotA\sec A,\cos A,\sin A,\cosec A,\cot A.

84. Express cosA,tanA,secA\cos A,\tan A,\sec A in terms of sinA\sin A.

85. Prove:secA(1sinA)(secA+tanA)=1.\sec A(1-\sin A)(\sec A+\tan A)=1.

86. Simplify:1+tan2Asec2A.\frac{1+\tan^2A}{\sec^2A}.

87. Simplify:cosec2A1cot2A.\frac{\cosec^2A-1}{\cot^2A}.

88. IfsinA=35,\sin A=\frac35,

verify thatsec2Atan2A=1.\sec^2A-\tan^2A=1.


H. Conceptual & Application-Based Questions

89. Why can the value of sinA\sin A never exceed 11 in a right triangle?

90. Why are cot0\cot0^\circ and cosec0\cosec0^\circ not defined?

91. Why are tan90\tan90^\circ and sec90\sec90^\circ not defined?

92. If two right triangles have the same acute angle but different side lengths, will their sine values be different? Give a reason.

93. If one side and one acute angle of a right triangle are known, can the remaining sides and angles be determined? Explain briefly.

94. A right triangle has one acute angle 3030^\circ and hypotenuse 1010 cm. Find the side opposite the 3030^\circ angle.

95. In a right triangle, one acute angle is 6060^\circ and the side adjacent to it is 55 cm. Find the hypotenuse.

96. Ifsin(AB)=12,cos(A+B)=12,\sin(A-B)=\frac12,\qquad \cos(A+B)=\frac12,

with A>BA>B and 0<A+B900^\circ<A+B\leq90^\circ, find AA and BB.


Answer Key

A. MCQs

QAnswerQAnswer
1C11B
2B12B
3C13B
4C14B
5B15B
6B16C
7C17B
8D18B
9C19B
10B20C

B. Fill in the Blanks

  1. sides, angles
  2. hypotenuse
  3. opposite side
  4. hypotenuse
  5. opposite side
  6. sinA\sin A
  7. cosA\cos A
  8. tanA\tan A
  9. sinA\sin A
  10. sinA\sin A
  11. 00
  12. 00
  13. 11
  14. 12\frac12
  15. 12\frac12
  16. 11
  17. sec2A\sec^2A
  18. cosec2A\cosec^2A
  19. not defined
  20. not defined

C. True/False

  1. False
  2. False
  3. True
  4. False
  5. True
  6. True
  7. False
  8. True
  9. True
  10. False
  11. True
  12. True
  13. False
  14. True

D. Assertion–Reason

  1. A
  2. A
  3. A
  4. A
  5. D
  6. A

E. Very Short Answers

  1. The branch of mathematics dealing with relationships between sides and angles of triangles.
  2. The side opposite the 9090^\circ angle; it is the longest side.

cotA\boxed{\cot A}

tanA=sinAcosA\boxed{\tan A=\frac{\sin A}{\cos A}}

cotA=cosAsinA\boxed{\cot A=\frac{\cos A}{\sin A}}

  1. 11
  2. 11
  3. 11
  4. 00

sin2A+cos2A=1\boxed{\sin^2A+\cos^2A=1}1+tan2A=sec2A\boxed{1+\tan^2A=\sec^2A}1+cot2A=cosec2A\boxed{1+\cot^2A=\cosec^2A}

F. Numerical Answers

sinA=35,cosA=45\boxed{\sin A=\frac35,\quad\cos A=\frac45}

cosA=1213,tanA=512\boxed{\cos A=\frac{12}{13},\quad\tan A=\frac5{12}}

sinA=817,secA=1715\boxed{\sin A=\frac8{17},\quad\sec A=\frac{17}{15}}

cosA=1213, sinA=513, tanA=512\boxed{\cos A=\frac{12}{13},\ \sin A=\frac5{13},\ \tan A=\frac5{12}}cosecA=135, cotA=125\boxed{\cosec A=\frac{13}{5},\ \cot A=\frac{12}{5}}

tanA=87\boxed{\tan A=\frac87}

Hypotenuse:82+152=17\sqrt{8^2+15^2}=17

Therefore:sinA=817, cosA=1517, tanA=815\boxed{\sin A=\frac8{17},\ \cos A=\frac{15}{17},\ \tan A=\frac8{15}}cosecA=178, secA=1715, cotA=158\boxed{\cosec A=\frac{17}{8},\ \sec A=\frac{17}{15},\ \cot A=\frac{15}{8}}

  1. Other side:

13252=12\sqrt{13^2-5^2}=12

For the angle opposite 55 cm:sinA=513,cosA=1213,tanA=512\boxed{\sin A=\frac5{13},\quad \cos A=\frac{12}{13},\quad \tan A=\frac5{12}}cosecA=135,secA=1312,cotA=125\boxed{\cosec A=\frac{13}{5},\quad \sec A=\frac{13}{12},\quad \cot A=\frac{12}{5}}

sin45=cos45=12\sin45^\circ=\cos45^\circ=\frac1{\sqrt2}

Hence:2sinAcosA=2(12)(12)=12\sin A\cos A =2\left(\frac1{\sqrt2}\right) \left(\frac1{\sqrt2}\right) =\boxed1

3232+1212=1\frac{\sqrt3}{2}\cdot\frac{\sqrt3}{2} +\frac12\cdot\frac12 =\boxed1

2(1)2+(32)2(32)2=22(1)^2+\left(\frac{\sqrt3}{2}\right)^2- \left(\frac{\sqrt3}{2}\right)^2 =\boxed2

G. Identity Answers

sec2Atan2A=1\boxed{\sec^2A-\tan^2A=1}

cosec2Acot2A=1\boxed{\cosec^2A-\cot^2A=1}

secA=23, cosA=32, sinA=12\boxed{\sec A=\frac2{\sqrt3},\ \cos A=\frac{\sqrt3}{2},\ \sin A=\frac12}cosecA=2,cotA=3\boxed{\cosec A=2,\quad \cot A=\sqrt3}

cosA=1sin2A\boxed{\cos A=\sqrt{1-\sin^2A}}tanA=sinA1sin2A\boxed{\tan A=\frac{\sin A}{\sqrt{1-\sin^2A}}}secA=11sin2A\boxed{\sec A=\frac1{\sqrt{1-\sin^2A}}}

For the acute-angle context of the chapter, the positive square root is used.

LHS=1=RHS\boxed{\text{LHS}=1=\text{RHS}}

1\boxed1

Sincecosec2A1=cot2A,\cosec^2A-1=\cot^2A,

the result is:1\boxed1

  1. Given:

sinA=35\sin A=\frac35

socosA=45,tanA=34,secA=54.\cos A=\frac45,\qquad \tan A=\frac34,\qquad \sec A=\frac54.

Therefore:sec2Atan2A=2516916=1.\sec^2A-\tan^2A =\frac{25}{16}-\frac9{16} =\boxed1.

H. Application/Conceptual Answers

  1. Because the hypotenuse is the longest side, so

oppositehypotenuse1.\frac{\text{opposite}}{\text{hypotenuse}}\leq1.

  1. Both involve division by sin0=0\sin0^\circ=0.
  2. Both involve division by cos90=0\cos90^\circ=0.
  3. No. Their sine values remain the same because the triangles are similar and corresponding sides remain proportional.
  4. Yes. A known side and an acute angle allow appropriate trigonometric ratios and Pythagoras’ theorem to determine the remaining quantities.

sin30=opposite10\sin30^\circ=\frac{\text{opposite}}{10}12=opposite10\frac12=\frac{\text{opposite}}{10}opposite=5 cm\boxed{\text{opposite}=5\text{ cm}}

cos60=5H\cos60^\circ=\frac5H12=5H\frac12=\frac5HH=10 cm\boxed{H=10\text{ cm}}

sin(AB)=12AB=30\sin(A-B)=\frac12 \Rightarrow A-B=30^\circ

andcos(A+B)=12A+B=60.\cos(A+B)=\frac12 \Rightarrow A+B=60^\circ.

Adding:2A=90A=452A=90^\circ\Rightarrow\boxed{A=45^\circ}

Thus: B=15∘​