Class 10 Science Electricity Notes

Class 10 Science — Electricity

Quality Notes | Chapter 11

1. Electric Current and Electric Circuit

Electric current is the rate at which electric charge passes through a cross-section of a conductor.

I=\frac{Q}{t}

Where:

  • (I) = current
  • (Q) = charge
  • (t) = time

SI unit: ampere (A)
1A=1C/s

In metallic conductors, electrons are the moving charges. However, conventional current is taken opposite to the direction of electron flow.

Electric Circuit

A closed, continuous conducting path through which current can flow is an electric circuit. Opening the switch breaks the path and stops the current.

Ammeter: measures current and is connected in series.


2. Electric Potential Difference

Charges do not normally flow through a conductor simply because the conductor exists. A potential difference is needed to drive charge through the circuit.

A cell or battery produces potential difference through chemical action.
V=\frac{W}{Q}

Where:

  • (V) = potential difference
  • (W) = work done
  • (Q) = charge

SI unit: volt (V)
1V=1J/C

Thus, a potential difference of 1 V means that 1 J of work is done in moving 1 C of charge between two points.

Voltmeter: measures potential difference and is connected in parallel across the required component.

Important relation
W=VQ


3. Ohm’s Law

For a metallic conductor whose temperature remains constant, the potential difference across it is directly proportional to the current through it.
V\propto I

Therefore,

[boxed{V=IR}

where (R) is the resistance.

Resistance

Resistance is the property of a conductor that opposes the flow of electric charge.
\boxed{R=\frac VI}

SI unit: ohm ((\Omega))
1\Omega=1V/A

From Ohm’s law:
\boxed{I=\frac VR}

So, for a fixed voltage, greater resistance means smaller current.

V–I Graph

For an ohmic conductor at constant temperature, the (V-I) graph is a straight line through the origin. Its constant ratio (V/I) represents resistance.


4. Factors Affecting Resistance

The resistance of a conductor depends mainly on:

  1. Length (l)
  2. Area of cross-section (A)
  3. Nature of material
  4. Temperature also affects resistance/resistivity.

For a uniform conductor:
R\propto l

and
R\propto\frac1A

Combining:
\boxed{R=\rho\frac lA}

where (\rho) is the resistivity of the material.

Key conclusions

  • Longer wire → greater resistance
  • Thicker wire → smaller resistance
  • Different materials → generally different resistances
  • Resistivity is a characteristic property of the material.

SI unit of resistivity: (\Omega,m).

Practical applications

  • Alloys generally have higher resistivity and can withstand high temperatures, so they are useful in heating devices.
  • Tungsten is used for bulb filaments because it has a very high melting point.
  • Copper and aluminium are used in transmission lines because of their low resistivity.

5. Combination of Resistors

Resistors can mainly be connected in:

  • Series
  • Parallel

A. Resistors in Series

Resistors connected end-to-end form a series combination.

Current

The same current passes through every resistor.
I=I_1=I_2=I_3

Potential difference
V=V_1+V_2+V_3

Equivalent resistance

boxed{R_s=R_1+R_2+R_3}

Therefore, series equivalent resistance is greater than any individual resistance.

Remember

Series → Same Current


B. Resistors in Parallel

In a parallel arrangement, the resistors are connected across the same two points.

Potential difference

The potential difference across every branch is the same:

V=V_1=V_2=V_3

Current

\boxed{I=I_1+I_2+I_3}

Equivalent resistance
\boxed{\frac1{R_p}

\frac1{R_1}+\frac1{R_2}+\frac1{R_3}

The equivalent resistance of a parallel combination is less than the smallest individual resistance.

Remember

Parallel → Same Voltage


Series vs Parallel — High-Value Comparison

SeriesParallel
Same current through each componentSame potential difference across each branch
(R_s=R_1+R_2+…)(\frac1{R_p}=\frac1{R_1}+\frac1{R_2}+…)
Equivalent resistance increasesEquivalent resistance decreases
Failure of one component can break the whole circuitOther branches can continue operating
Not suitable for domestic appliancesSuitable for domestic circuits

Domestic appliances are connected in parallel because different appliances can operate according to their individual current requirements, and failure of one does not necessarily stop the others.


6. Heating Effect of Electric Current

When current passes through a resistance, electrical energy can be converted into heat energy.

For a current (I) through resistance (R) for time (t):

\boxed{H=VIt}
Using Ohm’s law:

\boxed{H=I^2Rt}

This is Joule’s law of heating.

Joule’s law tells us:

H\propto I^2
for fixed (R,t);

H\propto R
for fixed (I,t);

H\propto t
for fixed (I,R).

Applications

The heating effect is used in:

  • electric iron
  • toaster
  • electric oven
  • electric kettle
  • electric heater
  • electric bulb
  • electric fuse

Electric Fuse

A fuse protects a circuit from excessively high current. It is connected in series. If excessive current flows, the fuse wire heats up, melts, and breaks the circuit.


7. Electric Power

Electric power is the rate at which electrical energy is consumed or converted.

\boxed{P=VI}
Using Ohm’s law:

\boxed{P=I^2R}
and

\boxed{P=\frac{V^2}{R}}
SI unit: watt (W)

1W=1V\times1A
A larger practical unit is:

1kW=1000W


8. Electrical Energy

Electrical energy consumed is:

\boxed{E=Pt}
Since (P=VI):

\boxed{E=VIt}
For a resistor, the same quantity can be expressed through the heating relation:

E=I^2Rt
Commercial Unit

Electrical energy supplied to homes is commonly measured in kilowatt-hour (kWh).

\boxed{1kWh=3.6\times10^6J}
One kWh is commonly called one unit of electricity.

Electricity Cost

\boxed{\text{Cost}=\text{Energy consumed in kWh}\times\text{Cost per kWh}}


9. Formula Sheet — Must Know

Current

\boxed{I=\frac Qt}
Potential difference

\boxed{V=\frac WQ}
Ohm’s law

\boxed{V=IR}
Resistance

\boxed{R=\frac VI}
Current

\boxed{I=\frac VR}
Resistance of a wire

\boxed{R=\rho\frac lA}
Series combination

\boxed{R_s=R_1+R_2+R_3}
Parallel combination

\boxed{\frac1{R_p}=
\frac1{R_1}+\frac1{R_2}+\frac1{R_3}}
Heat produced

\boxed{H=VIt=I^2Rt}
Electric power

\boxed{P=VI=I^2R=\frac{V^2}{R}}
Electrical energy

\boxed{E=Pt=VIt}
Energy conversion

\boxed{1kWh=3.6\times10^6J}


10. Exam-Focused Concept Triggers

If the question says…

  • Rate of flow of charge → Current
  • Work done per unit charge → Potential difference
  • Opposition to charge flow → Resistance
  • (V) directly proportional to (I) → Ohm’s law
  • Longer wire → Resistance increases
  • Thicker wire → Resistance decreases
  • Same current → Series
  • Same voltage → Parallel
  • Heat due to current → Joule heating
  • Rate of electrical energy consumption → Power
  • Commercial unit of electrical energy → kWh
  • Protective device against excessive current → Fuse

11. The Chapter in One Flow

Cell/Battery
↓ creates potential difference
Potential difference
↓ drives charge
Electric current
↓ encounters
Resistance
↓ obeys (V=IR) for an ohmic conductor at constant temperature
↓ produces
Heat (H=I^2Rt)
and electrical energy is consumed at a rate called
Power (P=VI).


Final Revision Priority

If you have limited time, learn these first:

  1. (I=Q/t)
  2. (V=W/Q)
  3. Ohm’s law: (V=IR)
  4. (R=\rho l/A)
  5. Series and parallel rules
  6. (H=I^2Rt)
  7. (P=VI=I^2R=V^2/R)
  8. (1,kWh=3.6\times10^6J)
  9. Ammeter → series
  10. Voltmeter → parallel
  11. Series → same current
  12. Parallel → same potential difference