CLASS 12 CHEMISTRY ELECTROCHEMISTRY MCQ

CHAPTER 2 – ELECTROCHEMISTRY IMPORTANT QUESTION BANK

MCQs + Fill in the Blanks + Assertion Reason + Very Short Questions

Assertion Reason + Very Short Questions

SECTION A: MULTIPLE CHOICE QUESTIONS (MCQs)

1. In a galvanic cell, conversion takes place from:

A. Electrical energy to chemical energy
B. Chemical energy to electrical energy
C. Heat energy to electrical energy
D. Light energy to chemical energy

Answer: B


2. Oxidation occurs at:

A. Cathode
B. Salt bridge
C. Anode
D. Electrolyte

Answer: C


3. In a galvanic cell, electrons flow from:

A. Cathode to anode
B. Anode to cathode
C. Salt bridge to cathode
D. Electrolyte to electrode

Answer: B


4. The standard electrode potential of Standard Hydrogen Electrode is:

A. 1 V
B. 0 V
C. –1 V
D. 0.5 V

Answer: B


5. The unit of conductivity is:

A. Ω
B. S m⁻¹
C. S⁻¹
D. mol m⁻¹

Answer: B


6. The function of a salt bridge is:

A. To increase resistance
B. To provide electrons
C. To maintain electrical neutrality
D. To stop ion movement

Answer: C


7. Cell potential is calculated by:

A. Anode − Cathode
B. Cathode − Anode
C. Cathode + Anode
D. Anode × Cathode

Answer: B


8. A positive value of E°cell indicates:

A. Non-spontaneous reaction
B. Equilibrium condition
C. Spontaneous reaction
D. No reaction

Answer: C


9. Nernst equation is used to calculate:

A. Atomic mass
B. Electrode potential under non-standard conditions
C. Molecular mass
D. Density

Answer: B


10. The value of Faraday constant is approximately:

A. 965 C mol⁻¹
B. 9650 C mol⁻¹
C. 96500 C mol⁻¹
D. 9.65 C mol⁻¹

Answer: C


11. Conductance is the reciprocal of:

A. Conductivity
B. Resistance
C. Resistivity
D. Cell constant

Answer: B


12. On dilution, conductivity of electrolyte solution:

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

Answer: B


13. On dilution, molar conductivity:

A. Decreases
B. Increases
C. Remains unchanged
D. Becomes zero

Answer: B


14. Strong electrolytes are:

A. Completely ionised
B. Not ionised
C. Weakly ionised
D. Insoluble

Answer: A


15. Which law explains independent migration of ions?

A. Faraday’s law
B. Ohm’s law
C. Kohlrausch’s law
D. Henry’s law

Answer: C


16. Weak electrolytes show a large increase in molar conductivity on dilution because:

A. Temperature increases
B. Ionisation increases
C. Resistance increases
D. Volume decreases

Answer: B


17. In electrolysis, reduction occurs at:

A. Anode
B. Cathode
C. Salt bridge
D. Electrolyte

Answer: B


18. Faraday’s first law relates deposited mass with:

A. Resistance
B. Voltage
C. Quantity of electricity
D. Temperature

Answer: C


19. The formula for mass deposited during electrolysis is:

A. m = IR
B. m = MIt/nF
C. m = nF/MI
D. m = VIt

Answer: B


20. Rust is chemically:

A. FeO
B. Fe₂O₃
C. Fe₂O₃·xH₂O
D. Fe(OH)₂

Answer: C


21. A rechargeable battery is:

A. Dry cell
B. Mercury cell
C. Lead storage battery
D. Primary cell

Answer: C


22. Hydrogen-oxygen fuel cell produces:

A. CO₂
B. H₂O
C. O₂
D. H₂O₂

Answer: B


23. In a lead storage battery, electrolyte used is:

A. HCl
B. NaOH
C. H₂SO₄
D. KOH

Answer: C


24. AC current is used in conductivity measurements because:

A. It increases temperature
B. It prevents electrolysis
C. It decreases ion movement
D. It increases resistance

Answer: B


25. Primary batteries are:

A. Rechargeable
B. Non-rechargeable
C. Fuel cells
D. Electrolytic cells

Answer: B


SECTION B: FILL IN THE BLANKS

1. The electrode where oxidation occurs is called ______.

Answer: Anode


2. The electrode where reduction occurs is called ______.

Answer: Cathode


3. Electrons flow from ______ to ______.

Answer: Anode to cathode


4. Standard hydrogen electrode has electrode potential equal to ______.

Answer: 0.00 V


5. The reciprocal of resistance is called ______.

Answer: Conductance


6. The unit of resistance is ______.

Answer: Ohm (Ω)


7. Kohlrausch’s law is applicable at ______ dilution.

Answer: Infinite


8. The value of Faraday constant is approximately ______ C mol⁻¹.

Answer: 96500


9. The process of coating a metal with zinc is called ______.

Answer: Galvanisation


10. The product formed during rusting of iron is ______.

Answer: Hydrated ferric oxide


11. The electrolyte used in lead storage battery is ______.

Answer: Sulphuric acid


12. Fuel cells convert ______ energy into electrical energy.

Answer: Chemical


13. Molar conductivity is represented by the symbol ______.

Answer: Λₘ


14. The unit of molar conductivity is ______.

Answer: S cm² mol⁻¹


15. Salt bridge contains an inert electrolyte like ______.

Answer: KCl/KNO₃


SECTION C: ASSERTION–REASON QUESTIONS

Q1.

Assertion: A galvanic cell produces electricity.
Reason: The reaction occurring in a galvanic cell is spontaneous.

A. Both true and reason explains assertion
B. Both true but reason does not explain
C. Assertion true, reason false
D. Assertion false, reason true

Answer: A


Q2.

Assertion: Molar conductivity increases on dilution.
Reason: Ion mobility increases and interionic attraction decreases.

Answer: A


Q3.

Assertion: Salt bridge is necessary in a galvanic cell.
Reason: It maintains electrical neutrality.

Answer: A


Q4.

Assertion: Primary batteries cannot be recharged.
Reason: Their chemical reactions are irreversible.

Answer: A


Q5.

Assertion: Conductivity decreases on dilution.
Reason: Number of ions per unit volume decreases.

Answer: A


SECTION D: VERY SHORT ANSWER QUESTIONS

1. What is electrochemistry?

Answer:
The branch of chemistry dealing with conversion between chemical energy and electrical energy.


2. What is a salt bridge?

Answer:
A U-shaped tube containing electrolyte that connects two half cells.


3. Define electrode potential.

Answer:
The potential difference developed between an electrode and electrolyte solution.


4. Write the formula for Gibbs energy.

Answer:ΔG=nFE\Delta G=-nFEΔG=−nFE


5. State Faraday’s first law.

Answer:
Mass deposited is directly proportional to quantity of electricity passed.


6. Name the rechargeable battery used in automobiles.

Answer:
Lead storage battery.


7. Name the fuel used in hydrogen fuel cell.

Answer:
Hydrogen.


8. What is corrosion?

Answer:
Slow deterioration of metals due to chemical or electrochemical reactions.


9. What is the SI unit of conductivity?

Answer:
S m⁻¹


10. What is the role of platinum in SHE?

Answer:
It acts as an inert electrode.

SECTION A: CASE-BASED QUESTIONS


CASE STUDY 1: DANIELL CELL

A Daniell cell consists of a zinc electrode dipped in ZnSO₄ solution and a copper electrode dipped in CuSO₄ solution. The two solutions are connected through a salt bridge. Zinc undergoes oxidation while copper ions undergo reduction.

Cell representation:ZnZn2+Cu2+CuZn|Zn^{2+}||Cu^{2+}|CuZn∣Zn2+∣∣Cu2+∣Cu


Q1. The electrode where zinc oxidation occurs is:

A. Cathode
B. Anode
C. Salt bridge
D. Electrolyte

Answer: B


Q2. The reaction at cathode is:

A.ZnZn2++2eZn\rightarrow Zn^{2+}+2e^-Zn→Zn2++2e−

B.Cu2++2eCuCu^{2+}+2e^-\rightarrow CuCu2++2e−→Cu

C.CuCu2++2eCu\rightarrow Cu^{2+}+2e^-Cu→Cu2++2e−

D.Zn2++2eZnZn^{2+}+2e^-\rightarrow ZnZn2++2e−→Zn

Answer: B


Q3. The function of salt bridge is:

A. Supply electrons
B. Increase voltage
C. Maintain electrical neutrality
D. Stop ion movement

Answer: C


Q4. Electrons move through external wire from:

A. Copper to zinc
B. Zinc to copper
C. Salt bridge to electrode
D. Cathode to anode

Answer: B


CASE STUDY 2: CONDUCTIVITY OF ELECTROLYTES

Conductivity of an electrolyte solution depends on the number of ions present and their mobility. On dilution, conductivity decreases but molar conductivity increases.


Q1. Conductivity is represented by:

A. R
B. κ
C. Λₘ
D. E°

Answer: B


Q2. Molar conductivity increases on dilution because:

A. Number of ions decreases
B. Ionisation and mobility increase
C. Resistance becomes infinite
D. Temperature decreases

Answer: B


Q3. Weak electrolytes show a sharp increase in molar conductivity because:

A. They become insoluble
B. Their ionisation increases
C. They stop conducting
D. Their mass increases

Answer: B


Q4. Strong electrolytes are:

A. Completely ionised
B. Not ionised
C. Insoluble
D. Non-conducting

Answer: A


CASE STUDY 3: ELECTROLYSIS

During electrolysis, electrical energy is converted into chemical energy. Reduction takes place at cathode and oxidation takes place at anode.


Q1. In an electrolytic cell, cathode is:

A. Positive
B. Negative
C. Neutral
D. Absent

Answer: B


Q2. Faraday’s first law states that:

A. Voltage depends on resistance
B. Mass deposited depends on charge passed
C. Current depends on temperature
D. Resistance depends on length

Answer: B


Q3. Formula for deposited mass is:

A.m=IRm=IRm=IR

B.m=MItnFm=\frac{MIt}{nF}m=nFMIt​

C.m=VItm=VItm=VIt

D.m=nFMIm=\frac{nF}{MI}m=MInF​

Answer: B


SECTION B: ASSERTION–REASON QUESTIONS


Q1.

Assertion: A positive value of E°cell indicates a spontaneous reaction.
Reason: ΔG° is negative for a spontaneous reaction.

Answer: A
(Both statements are true and reason correctly explains assertion.)


Q2.

Assertion: Conductivity decreases on dilution.
Reason: Number of ions per unit volume decreases.

Answer: A


Q3.

Assertion: Molar conductivity of weak electrolytes increases greatly on dilution.
Reason: Degree of ionisation increases on dilution.

Answer: A


Q4.

Assertion: Salt bridge prevents direct mixing of solutions.
Reason: It contains an electrolyte in gel form.

Answer: A


Q5.

Assertion: Lead storage battery can be recharged.
Reason: Its chemical reactions are reversible.

Answer: A


SECTION C: MATCH THE FOLLOWING

Q1.

Column IColumn II
AnodeOxidation
CathodeReduction
Salt bridgeMaintains neutrality
SHE0 V

Answer:

  • Anode → Oxidation
  • Cathode → Reduction
  • Salt bridge → Maintains neutrality
  • SHE → 0 V

Q2.

Column IColumn II
Dry cellPrimary battery
Lead storage batterySecondary battery
Hydrogen fuel cellWater as product
RustFe₂O₃·xH₂O

Answer:

  • Dry cell → Primary battery
  • Lead storage battery → Secondary battery
  • Hydrogen fuel cell → Water as product
  • Rust → Fe₂O₃·xH₂O

Q3.

Column IColumn II
Conductance1/R
Cell constantl/A
Gibbs energy-nFE
Nernst equationNon-standard potential

Answer:

  • Conductance → 1/R
  • Cell constant → l/A
  • Gibbs energy → -nFE
  • Nernst equation → Non-standard potential

SECTION D: ONE-MARK IMPORTANT QUESTIONS

1. Which electrode is positive in a galvanic cell?

Answer: Cathode


2. Which electrode is positive in an electrolytic cell?

Answer: Anode


3. Name the law used to calculate limiting molar conductivity.

Answer: Kohlrausch’s law


4. What is the value of n in Zn → Zn²⁺ + 2e⁻?

Answer: 2


5. Which battery is used in automobiles?

Answer: Lead storage battery


6. What is the product of hydrogen-oxygen fuel cell?

Answer: Water


7. What type of reaction occurs at anode?

Answer: Oxidation


8. What is the SI unit of molar conductivity?

Answer: S m² mol⁻¹


9. Which gas is released at anode during electrolysis of molten NaCl?

Answer: Chlorine


10. What protects iron from corrosion by zinc coating?

Answer: Galvanisation

PART 10: IMPORTANT LONG ANSWER QUESTIONS (3 & 5 MARKS)

Board Exam Writing Practice


Q1. Explain the construction and working of a Daniell cell.

Answer:

A Daniell cell is a galvanic cell that converts chemical energy into electrical energy.

Construction:

It consists of:

  • A zinc electrode dipped in ZnSO₄ solution.
  • A copper electrode dipped in CuSO₄ solution.
  • The two solutions are connected through a salt bridge.
  • Electrodes are connected externally by a wire.

Cell notation:ZnZn2+Cu2+CuZn|Zn^{2+}||Cu^{2+}|CuZn∣Zn2+∣∣Cu2+∣Cu


Working:

At zinc electrode, oxidation occurs:ZnZn2++2eZn\rightarrow Zn^{2+}+2e^-Zn→Zn2++2e−

Zinc acts as anode.

At copper electrode, reduction occurs:Cu2++2eCuCu^{2+}+2e^-\rightarrow CuCu2++2e−→Cu

Copper acts as cathode.

Overall reaction:Zn+Cu2+Zn2++CuZn+Cu^{2+}\rightarrow Zn^{2+}+CuZn+Cu2+→Zn2++Cu

Electrons flow from zinc electrode to copper electrode through the external circuit.


Role of Salt Bridge:

  1. Maintains electrical neutrality.
  2. Completes the electrical circuit.
  3. Prevents direct mixing of solutions.
  4. Reduces liquid junction potential.

Q2. Derive the Nernst equation for electrode potential.

Answer:

For an electrochemical reaction:Oxidised form+neReduced formOxidised\ form+ne^-\rightarrow Reduced\ formOxidised form+ne−→Reduced form

The Gibbs energy change is related to electrode potential:ΔG=nFE\Delta G=-nFEΔG=−nFE

Under standard conditions:ΔG=nFE\Delta G^\circ=-nFE^\circΔG∘=−nFE∘

From thermodynamics:ΔG=ΔG+RTlnQ\Delta G=\Delta G^\circ+RT\ln QΔG=ΔG∘+RTlnQ

Substituting:nFE=nFE+RTlnQ-nFE=-nFE^\circ+RT\ln Q−nFE=−nFE∘+RTlnQ

Rearranging:E=ERTnFlnQE=E^\circ-\frac{RT}{nF}\ln QE=E∘−nFRT​lnQ

This is the Nernst equation.

At 298 K:E=E0.0591nlogQ\boxed{E=E^\circ-\frac{0.0591}{n}\log Q}E=E∘−n0.0591​logQ​


Q3. Derive the relation between Gibbs energy and cell potential.

Answer:

The maximum electrical work obtained from a cell is:Welectrical=nFEcellW_{electrical}=nFE_{cell}Welectrical​=nFEcell​

Gibbs energy change is equal to negative of maximum useful work:ΔG=nFEcell\Delta G=-nFE_{cell}ΔG=−nFEcell​

For standard conditions:ΔG=nFEcell\boxed{\Delta G^\circ=-nFE^\circ_{cell}}ΔG∘=−nFEcell∘​​

Conclusions:

  • If E°cell is positive → ΔG° is negative → reaction is spontaneous.
  • If E°cell is negative → ΔG° is positive → reaction is non-spontaneous.

Q4. Explain Kohlrausch’s law and its applications.

Answer:

Kohlrausch’s Law:

At infinite dilution, each ion contributes independently to the total molar conductivity of an electrolyte.

For an electrolyte:AxByxA++yBA_xB_y\rightarrow xA^{+}+yB^{-}Ax​By​→xA++yB− Λm=xλA+yλB\Lambda_m^\circ=x\lambda_A^\circ+y\lambda_B^\circΛm∘​=xλA∘​+yλB∘​


Applications:

1. Finding limiting molar conductivity of weak electrolytes

Weak electrolytes cannot be measured directly at infinite dilution.

Example:Λm(CH3COOH)\Lambda_m^\circ(CH_3COOH)Λm∘​(CH3​COOH)

is calculated using strong electrolytes.


2. Finding degree of dissociation

α=ΛmΛm\alpha=\frac{\Lambda_m}{\Lambda_m^\circ}α=Λm∘​Λm​​


3. Finding dissociation constant

Ka=cα21αK_a=\frac{c\alpha^2}{1-\alpha}Ka​=1−αcα2​


4. Finding solubility of sparingly soluble salts

S=1000κΛmS=\frac{1000\kappa}{\Lambda_m^\circ}S=Λm∘​1000κ​


Q5. Explain the variation of molar conductivity with concentration.

Answer:

Molar conductivity is represented by:Λm\Lambda_mΛm​

It changes differently for strong and weak electrolytes.


Strong Electrolytes:

Examples:

  • NaCl
  • KCl
  • HCl

Characteristics:

  • Completely ionised.
  • Molar conductivity increases slowly on dilution.

Reason:

  • Interionic attraction decreases.
  • Ion mobility increases.

Weak Electrolytes:

Examples:

  • CH₃COOH
  • NH₄OH

Characteristics:

  • Partially ionised.
  • Molar conductivity increases sharply on dilution.

Reason:

  • Degree of ionisation increases.
  • More ions are produced.

Q6. State and explain Faraday’s laws of electrolysis.

Answer:

Faraday’s First Law:

The mass of substance deposited at an electrode is directly proportional to the quantity of electricity passed.mQm\propto Qm∝Q

Since:Q=ItQ=ItQ=It

Therefore:m=ZItm=ZItm=ZIt


Faraday’s Second Law:

When the same quantity of electricity is passed through different electrolytes, the masses deposited are proportional to their equivalent masses.mMnm\propto \frac{M}{n}m∝nM​


Combined equation:m=MItnF\boxed{m=\frac{MIt}{nF}}m=nFMIt​​


Q7. Explain the working of a hydrogen-oxygen fuel cell.

Answer:

A hydrogen-oxygen fuel cell converts chemical energy directly into electrical energy.

Fuel:

  • Hydrogen
  • Oxygen

Anode Reaction:

2H2+4OH4H2O+4e2H_2+4OH^-\rightarrow4H_2O+4e^-2H2​+4OH−→4H2​O+4e−


Cathode Reaction:

O2+2H2O+4e4OHO_2+2H_2O+4e^-\rightarrow4OH^-O2​+2H2​O+4e−→4OH−


Overall Reaction:

2H2+O22H2O2H_2+O_2\rightarrow2H_2O2H2​+O2​→2H2​O


Advantages:

  1. High efficiency.
  2. Environment friendly.
  3. Water is the only product.
  4. Continuous electricity production is possible.

Q8. Explain corrosion of iron and methods of prevention.

Answer:

Corrosion is the slow deterioration of metals due to chemical or electrochemical reactions with the environment.


Rusting of Iron:

Anode reaction:

FeFe2++2eFe\rightarrow Fe^{2+}+2e^-Fe→Fe2++2e−


Cathode reaction:

O2+2H2O+4e4OHO_2+2H_2O+4e^-\rightarrow4OH^-O2​+2H2​O+4e−→4OH−


Formation of rust:Fe2O3.xH2OFe_2O_3.xH_2OFe2​O3​.xH2​O


Prevention Methods:

1. Painting

Prevents contact with air and moisture.

2. Galvanisation

Coating iron with zinc.

3. Electroplating

Depositing a protective metal layer.

4. Alloy formation

Example: Stainless steel.


MOST IMPORTANT 5-MARK QUESTIONS TO PRACTICE

⭐ Derivation of Nernst equation
⭐ Daniell cell construction and working
⭐ Kohlrausch’s law and applications
⭐ Faraday laws with formula
⭐ Fuel cell working
⭐ Corrosion mechanism and prevention
⭐ Relation between ΔG°, E°cell and K

PART 11: ONE-SHOT REVISION SHEET + MIND MAP

ELECTROCHEMISTRY: COMPLETE CHAPTER MAP

                    ELECTROCHEMISTRY

                           |
        -----------------------------------------
        |                                       |
 Electrochemical Cells                 Electrolytic Cells
        |                                       |
  Chemical → Electrical              Electrical → Chemical
        |
  ----------------
  |              |
Anode          Cathode
Oxidation     Reduction

1. ELECTROCHEMICAL CELLS

Galvanic Cell

Definition:

A cell that converts chemical energy into electrical energy through a spontaneous reaction.

Example:

Daniell Cell:ZnZn2+Cu2+CuZn|Zn^{2+}||Cu^{2+}|CuZn∣Zn2+∣∣Cu2+∣Cu


Electrode Reactions:

Anode:

ZnZn2++2eZn\rightarrow Zn^{2+}+2e^-Zn→Zn2++2e−

(Oxidation)

Cathode:

Cu2++2eCuCu^{2+}+2e^-\rightarrow CuCu2++2e−→Cu

(Reduction)


Remember:

AN OX

Anode → Oxidation

RED CAT

Reduction → Cathode


2. SALT BRIDGE

Functions:

✔ Maintains electrical neutrality
✔ Completes electrical circuit
✔ Prevents direct mixing of solutions
✔ Minimises liquid junction potential


3. ELECTRODE POTENTIAL

Standard Conditions:

  • Temperature = 298 K
  • Concentration = 1 M
  • Pressure = 1 bar

Standard Hydrogen Electrode (SHE)

E=0.00VE^\circ=0.00VE∘=0.00V

Used as reference electrode.


4. CELL EMF

Formula:Ecell=EcathodeEanode\boxed{E^\circ_{cell}=E^\circ_{cathode}-E^\circ_{anode}}Ecell∘​=Ecathode∘​−Eanode∘​​


Spontaneity Rule:

Positive E°cell

→ Spontaneous reaction

→ ΔG° negative


Negative E°cell

→ Non-spontaneous reaction

→ ΔG° positive


5. NERNST EQUATION

Used for calculating electrode potential under non-standard conditions.E=E0.0591nlogQ\boxed{E=E^\circ-\frac{0.0591}{n}\log Q}E=E∘−n0.0591​logQ​

(at 298 K)


Reaction Quotient:

Products concentration / Reactants concentration


6. IMPORTANT RELATIONS

Gibbs Energy:

ΔG=nFE\boxed{\Delta G=-nFE}ΔG=−nFE​


Standard Gibbs Energy:

ΔG=nFE\boxed{\Delta G^\circ=-nFE^\circ}ΔG∘=−nFE∘​


Equilibrium Constant:

E=0.0591nlogK\boxed{E^\circ=\frac{0.0591}{n}\log K}E∘=n0.0591​logK​


7. CONDUCTANCE

Resistance

R=ρlAR=\rho\frac{l}{A}R=ρAl​

Unit:

Ω


Conductance

G=1RG=\frac1RG=R1​

Unit:

Siemens (S)


Conductivity

κ=1ρ\kappa=\frac1\rhoκ=ρ1​

Unit:

S m⁻¹


8. CELL CONSTANT

Formula:lA\boxed{\frac{l}{A}}Al​​


Conductivity:κ=Cell ConstantR\boxed{\kappa=\frac{\text{Cell Constant}}{R}}κ=RCell Constant​​


9. MOLAR CONDUCTIVITY

Formula:Λm=κ×1000M\boxed{\Lambda_m=\frac{\kappa\times1000}{M}}Λm​=Mκ×1000​​


Effect of Dilution:

Conductivity:

Decreases

Reason:

Number of ions per unit volume decreases.


Molar Conductivity:

Increases

Reason:

  • Ion mobility increases.
  • Interionic attraction decreases.

10. STRONG VS WEAK ELECTROLYTES

Strong ElectrolyteWeak Electrolyte
Completely ionisedPartially ionised
High conductivityLow conductivity
Small increase in ΛmLarge increase in Λm
NaCl, HClCH₃COOH

11. KOHLRAUSCH’S LAW

Statement:

At infinite dilution, each ion contributes independently to the total molar conductivity.


Formula:Λm=λ++λ\Lambda_m^\circ=\lambda^\circ_+ +\lambda^\circ_-Λm∘​=λ+∘​+λ−∘​


Applications:

✔ Calculate Λ°m of weak electrolytes

✔ Calculate degree of dissociationα=ΛmΛm\alpha=\frac{\Lambda_m}{\Lambda_m^\circ}α=Λm∘​Λm​​

✔ Calculate dissociation constantKa=cα21αK_a=\frac{c\alpha^2}{1-\alpha}Ka​=1−αcα2​


12. ELECTROLYSIS

Electrolytic Cell:

Electrical energy → Chemical energy


Electrode Rules:

Cathode:

Negative

Reduction occurs


Anode:

Positive

Oxidation occurs


13. FARADAY’S LAWS

First Law:

Mass deposited is directly proportional to charge passed.mQm\propto Qm∝Q


Second Law:

Mass deposited depends on equivalent mass.


Formula:

m=MItnF\boxed{m=\frac{MIt}{nF}}m=nFMIt​​


Faraday Constant:

F=96500Cmol1\boxed{F=96500Cmol^{-1}}F=96500Cmol−1​


14. BATTERIES

Primary Batteries

  • Non-rechargeable
  • Irreversible reactions

Examples:

✔ Dry cell
✔ Mercury cell


Secondary Batteries

  • Rechargeable
  • Reversible reactions

Examples:

✔ Lead storage battery
✔ Lithium-ion battery


15. FUEL CELLS

Hydrogen-Oxygen Fuel Cell

Reaction:2H2+O22H2O2H_2+O_2\rightarrow2H_2O2H2​+O2​→2H2​O


Advantages:

✔ High efficiency
✔ Environment friendly
✔ Water is the only product


16. CORROSION

Definition:

Slow destruction of metals due to chemical/electrochemical reactions.


Rust Formation

Anode:

FeFe2++2eFe\rightarrow Fe^{2+}+2e^-Fe→Fe2++2e−


Cathode:

O2+2H2O+4e4OHO_2+2H_2O+4e^-\rightarrow4OH^-O2​+2H2​O+4e−→4OH−


Rust:Fe2O3.xH2OFe_2O_3.xH_2OFe2​O3​.xH2​O


Prevention:

✔ Painting
✔ Oiling
✔ Galvanisation
✔ Electroplating
✔ Alloy formation


LAST 15-MINUTE REVISION TABLE

TopicMust Remember
SHE0 V
Electron flowAnode → Cathode
OxidationAnode
ReductionCathode
E°cell formulaCathode − Anode
ΔG formula-nFE
Nernst equationE = E° − 0.0591/n log Q
Faraday constant96500 C mol⁻¹
Salt bridgeMaintains neutrality
RustFe₂O₃·xH₂O
Fuel cell productWater