1. Introduction
This chapter explores geometry with lines, specifically three lines intersecting in different ways. You will learn about:
- Types of lines
- Points of intersection
- Angles formed
- Properties and relationships of these angles
It strengthens understanding of angles, triangles, and line interactions in geometry.
2. Key Concepts
2.1 Types of Lines
- Intersecting Lines – Lines that meet at a point.
- Concurrent Lines – Three or more lines that meet at a single point.
- Non-intersecting Lines – Lines that do not meet (parallel lines).
2.2 Points of Intersection
- The point where two lines meet is called the point of intersection.
- If three lines meet at one point, that point is called the point of concurrency.
Example:
- In a triangle, medians are concurrent at the centroid.
- Altitudes meet at the orthocenter.
2.3 Angles Formed by Intersecting Lines
- Vertically Opposite Angles – Equal
- Adjacent Angles – Sum = 180° (linear pair)
- Exterior Angles – Related to interior angles in triangles
Example:
- Three lines intersect at a point. You can label angles as ∠1, ∠2, ∠3…
- Use properties of angles to calculate unknown angles.
2.4 Special Cases
- Concurrent Lines in Triangles
- Medians: Meet at centroid, divide medians in 2:1 ratio.
- Altitudes: Meet at orthocenter.
- Angle bisectors: Meet at incenter.
- Three lines forming a triangle
- Each pair intersects, forming three vertices.
- Angles inside triangle sum = 180°.
2.5 Properties
- Vertically opposite angles are equal
- Sum of angles on a straight line = 180°
- Three concurrent lines can divide a plane into six angles at intersection
- If three medians meet at centroid, each median divides triangle into equal areas
2.6 Real-Life Applications
- Traffic intersections (three roads meeting)
- Bridges or supports forming triangles
- Geometric design in architecture and art
3. Summary Table
| Concept | Key Points |
|---|---|
| Intersecting lines | Meet at a point, form vertically opposite & adjacent angles |
| Concurrent lines | Three or more lines meeting at a single point |
| Triangles & concurrency | Medians → centroid, Altitudes → orthocenter, Angle bisectors → incenter |
| Angles | Linear pair = 180°, Vertically opposite = equal |
| Real-life | Road intersections, structural supports, geometric design |
Questions
Section A: Multiple Choice Questions (MCQs) – 10 Questions
- Two lines that meet at a point are called:
a) Parallel lines
b) Intersecting lines
c) Perpendicular lines
d) Skew lines - Three lines that meet at a single point are called:
a) Intersecting lines
b) Concurrent lines
c) Parallel lines
d) Perpendicular lines - The point where medians of a triangle meet is called:
a) Circumcenter
b) Incenter
c) Centroid
d) Orthocenter - The sum of angles on a straight line is:
a) 90°
b) 180°
c) 360°
d) 270° - Vertically opposite angles are:
a) Equal
b) Supplementary
c) Complementary
d) None of these - In a triangle, altitudes meet at the:
a) Centroid
b) Orthocenter
c) Incenter
d) Circumcenter - Angle bisectors of a triangle meet at the:
a) Centroid
b) Orthocenter
c) Incenter
d) Circumcenter - How many angles are formed when three lines intersect at a single point (not concurrent)?
a) 3
b) 4
c) 6
d) 8 - If three medians of a triangle intersect, each median is divided in the ratio:
a) 1:1
b) 2:1
c) 3:1
d) 1:2 - Which of the following is a real-life example of three concurrent lines?
a) Roads meeting at a traffic point
b) Parallel railway tracks
c) Two intersecting bridges
d) A straight canal
Section B: Fill in the Blanks – 10 Questions
- Three lines intersecting at a single point are called _______.
- The point of concurrency of medians is called _______.
- The point where altitudes meet is called _______.
- Angle bisectors meet at the _______ of the triangle.
- Sum of angles around a point = _______ degrees.
- Vertically opposite angles are always _______.
- Adjacent angles on a straight line add up to _______.
- In a triangle, three medians divide each median in the ratio _______.
- If three lines form a triangle, there are _______ vertices.
- Three intersecting lines can divide the plane into a maximum of _______ regions.
Section C: Short Answer Questions – 10 Questions
- Draw two intersecting lines and label vertically opposite angles.
- Draw three concurrent lines intersecting at one point and label angles.
- In a triangle, draw medians and mark the centroid.
- In a triangle, draw altitudes and mark the orthocenter.
- Name the three points of concurrency in a triangle.
- If a linear pair of angles is 70°, find the other angle.
- How many angles are formed if two lines intersect? Draw and label.
- Draw three lines forming a triangle and label the vertices.
- Identify which type of concurrency (medians, altitudes, angle bisectors) is used in the following figure.
- If three concurrent lines intersect, how many distinct angles are formed at the point of concurrency?
Section D: Long Answer / Problem-Solving – 10 Questions
- A triangle has three medians intersecting at centroid G. One median measures 9 cm. Find the length of segments divided by the centroid.
- In a triangle, altitudes meet at orthocenter H. Draw and mark all angles.
- Prove that vertically opposite angles are equal when two lines intersect.
- Prove that the sum of angles on a straight line = 180°.
- Draw three lines that are not concurrent but intersect to form a triangle. Label angles and vertices.
- In triangle ABC, medians AD, BE, CF meet at G. If AG=6 cm, find GD.
- Three lines intersect at one point forming angles in ratio 2:3:5. Find all angles.
- Show using a diagram that three altitudes of a triangle are concurrent.
- Draw a triangle and its angle bisectors; mark the incenter and draw the incircle.
- Three lines intersect forming a six-angle pattern. If one angle is 40°, find the remaining angles assuming two pairs of equal angles.
Section E: Application / Higher-Order Thinking – 10 Questions
- A road map shows three roads meeting at a single traffic circle. Identify point of concurrency and label angles formed.
- If three concurrent lines divide a triangular garden into six small triangles, draw and label.
- A triangular bridge support has three beams meeting at a point. Identify centroid and explain why.
- Draw a diagram showing three concurrent lines and calculate the angles if one is 50° and vertically opposite angles are equal.
- A triangular park has medians, altitudes, and angle bisectors drawn. Identify all points of concurrency.
- In an intersection with three roads, angles formed are 30°, 70°, 80°. Verify sum of angles around the point.
- Draw three lines intersecting to form a triangle and a smaller triangle inside formed by medians. Label centroid.
- If three altitudes of a triangle meet outside the triangle (obtuse triangle), draw and mark orthocenter.
- Real-life problem: Identify points of concurrency in a triangular roof truss and explain their significance.
- Three lines intersect forming a triangle. If one angle is 60° and another 50°, find the third angle.
Answers – Chapter 7: A Tale of Three Intersecting Lines
Section A: MCQs – Answers
- b) Intersecting lines – Lines that meet at a point.
- b) Concurrent lines – Three or more lines meeting at one point.
- c) Centroid – Point where medians intersect.
- b) 180° – Sum of angles on a straight line.
- a) Equal – Vertically opposite angles are equal.
- b) Orthocenter – Point where altitudes meet.
- c) Incenter – Point where angle bisectors meet.
- c) 6 – Three lines intersecting at a point (not concurrent) form 6 angles.
- b) 2:1 – Each median is divided by centroid in a 2:1 ratio.
- a) Roads meeting at a traffic point – Real-life example of concurrency.
Section B: Fill in the Blanks – Answers
- Concurrent lines
- Centroid
- Orthocenter
- Incenter
- 360° – Sum of angles around a point.
- Equal – Vertically opposite angles.
- 180° – Linear pair.
- 2:1 – Ratio of segments divided by centroid.
- 3 vertices – Triangle formed by three lines.
- 7 regions – Maximum regions divided by three intersecting lines.
(Quick reasoning: Each new line can divide existing regions into maximum new areas. For three lines not all concurrent: 1 + 3 + 3 = 7 regions.)
Section C: Short Answer Questions – Answers
- Two intersecting lines: Label angles ∠1, ∠2 vertically opposite → ∠1=∠2
- Three concurrent lines: Draw lines meeting at point O → label six angles around point.
- Triangle medians: Draw triangle ABC, medians AD, BE, CF meet at G (centroid).
- Triangle altitudes: Draw altitudes from vertices → meet at H (orthocenter).
- Points of concurrency: Centroid (medians), Orthocenter (altitudes), Incenter (angle bisectors).
- Linear pair = 180° → Other angle = 180°−70° = 110°
- Two intersecting lines form 4 angles (2 pairs of vertically opposite angles).
- Three lines forming a triangle → 3 vertices labeled A, B, C.
- Identify concurrency type by diagram: e.g., medians → centroid, altitudes → orthocenter.
- Three concurrent lines → 6 angles at the point of concurrency.
Section D: Long Answer / Problem-Solving – Answers
- Median = 9 cm, centroid divides median 2:1 → AG:GD=2:1 → AG=6 cm, GD=3 cm
- Altitudes meet at orthocenter H → Draw from each vertex perpendicular to opposite side
- Proof: Vertically opposite angles are equal:
- Let two intersecting lines AB and CD intersect at O
- ∠AOC and ∠BOD are vertically opposite → equal by geometry
- Proof linear pair sum = 180°:
- Angles on straight line form straight angle = 180°
- ∴ Adjacent angles sum = 180°
- Draw three intersecting lines forming a triangle → Label angles ∠A, ∠B, ∠C
- Median AG=6 cm → centroid divides median 2:1 → GD=3 cm
- Three angles in ratio 2:3:5 → Total = 360° at point → Sum=360°
- Let angles = 2x, 3x, 5x → 2x+3x+5x=360 → 10x=360 → x=36°
- Angles = 72°, 108°, 180°
- Draw triangle → Draw altitudes → Verify all meet at H
- Draw triangle → Draw angle bisectors → mark incenter → draw incircle touching all sides
- Three lines intersect forming six angles → If one =40°, vertically opposite =40°, adjacent angles sum=180 → calculate others accordingly
Section E: Application / Higher-Order Thinking – Answers
- Traffic circle → point of concurrency → draw three roads → six angles around point
- Triangle with medians → six small triangles inside → draw and label centroid
- Bridge truss → three beams meet at point → centroid → provides structural balance
- Diagram → Draw three concurrent lines → angle 50° → vertically opposite also 50° → linear pairs 130°
- Triangle → draw medians, altitudes, angle bisectors → identify centroid, orthocenter, incenter
- Intersection with three roads: angles =30°+70°+80°=180° → Around point sum=360° verified
- Triangle → medians → smaller triangle inside → centroid labeled
- Altitudes meet outside triangle (obtuse) → orthocenter outside → draw diagram
- Triangular roof truss → points of concurrency → centroid ensures weight distribution
- Triangle angles: 60°+50°=110° → third angle = 180−110 = 70°