Potential Energy Worksheet | PDF

Potential Energy Worksheet | PDF

Potential Energy WorksheetDownload

Answer Key — Potential Energy Worksheet

A. MCQs

  1. b) Potential
  2. c) Joule
  3. c) Mass and height
  4. c) 50 J
  5. c) Double
  6. a) 2 kg at 5 m (100 J; note: option d is also 100 J, so this question has two correct answers.)

B. Fill in the Blanks

  1. Gravitational
  2. Joule (J)
  3. mgh
  4. Zero
  5. Increases
  6. Elastic

C. True or False

  1. True
  2. False
  3. True
  4. True
  5. False
  6. True

D. Match the Following

  1. e
  2. c
  3. b
  4. d
  5. a

E. Very Short Answer

  1. Energy possessed by an object due to its position or configuration.
  2. Mass and height.
  3. It increases.
  4. A book kept on a shelf.
  5. A stretched rubber band.

F. Numerical Questions

  1. PE=5×10×4=200 JPE=5\times10\times4=\boxed{200\,J}
  2. PE=10×10×6=600 JPE=10\times10\times6=\boxed{600\,J}
  3. 800=m×10×10800=m\times10\times10
    m=8 kg\boxed{m=8\,kg}
  4. 200=4×10×h200=4\times10\times h
    h=5 m\boxed{h=5\,m}
  5. Increase in height =8−3=5 m=8-3=5\,m
    ΔPE=2×10×5=100 J\Delta PE=2\times10\times5=\boxed{100\,J}

G. Assertion–Reason

  1. A
  2. D

H. Case-Based

a) Gravitational potential energy
b) 4×10×2=80 J4\times10\times2=\boxed{80\,J}
c) 4×10×4=160 J4\times10\times4=\boxed{160\,J}
d) Mass

a) Decreases
b) Increases
c) Gravitational PE → Kinetic energy
d) Kinetic energy

I. HOTS / Application

  1. The ball at 8 m, because PE is directly proportional to height.
  2. A: 5×10×6=300 J5\times10\times6=300\,J
    B: 10×10×3=300 J10\times10\times3=300\,J
    Yes, both have 300 J.
  3. No. A stationary object can possess potential energy because energy can be stored due to its position.
  4. Because the elevated water has gravitational potential energy, which can be converted into kinetic energy and then used to do work.
  5. PE=15×10×10=1500 JPE=15\times10\times10=\boxed{1500\,J}
    The energy comes from the work done by the climber in lifting the bag.

J. Challenge

  1. A: PEA=mghPE_A=mgh
    B: PEB=(2m)g(h/2)=mghPE_B=(2m)g(h/2)=mgh
    Therefore, PEA=PEBPE_A=PE_B.
  2. PE=mghPE=mgh
    Mass ×2 and height ×3 → PE becomes 2×3=62\times3=6 times.
  3. 100=2×10×h⇒h=5 m100=2\times10\times h\Rightarrow h=5\,m
    New height =10 m=10\,m.
    100=m×10×10100=m\times10\times10
    m=1 kg\boxed{m=1\,kg}