Class 10 Mathematics Worksheet
Chapter: Polynomials
Name: _______________________ Roll No.: _____________ Date: _____________
Section A – Identify the Degree (10 Questions)
Find the degree of each polynomial.
- 5×3−2x+7
- 4×5+9
- 7×2−5x+3
- 8−3×4+x6
- 12x
- 15
- x8+x2+1
- 9×7−4×3+x
- 2×9−5×6+8×2
- 11×4−9×2+6
Section B – Find the Zeros (15 Questions)
Find the zero(s) of each polynomial.
- x−8
- x+15
- 2x−10
- 5x+20
- x2−25
- x2−64
- x2−16x+64
- x2−9x+20
- x2−13x+42
- x2−11x+24
- x2+7x+12
- x2−10x+21
- 2×2−14x+24
- 3×2−12x+9
- x2−100
Section C – Verify the Relationship Between Zeros and Coefficients (10 Questions)
Find the zeros and verify:
- x2−5x+6
- x2−7x+10
- x2−8x+15
- x2+9x+20
- x2−12x+35
- 2×2−9x+10
- 3×2−13x+12
- 4×2−20x+24
- 5×2−15x+10
- 6×2−11x−10
Section D – Divide Using Polynomial Division (10 Questions)
- Divide x2+7x+12 by x+3.
- Divide x2−9 by x−3.
- Divide 2×2+9x+10 by x+2.
- Divide 3×2−15x+18 by x−2.
- Divide x3−8 by x−2.
- Divide x3+27 by x+3.
- Divide 2×3+5×2−4x−3 by x−1.
- Divide 3×3−7×2+2x+8 by x+2.
- Divide 4×3+8×2−9x−18 by x+2.
- Divide 5×3−20×2+15x by x−1.
Section E – Use the Remainder Theorem (10 Questions)
Find the remainder.
- p(x)=2×3+5×2−4x+1,x−2
- p(x)=x3−7x+9,x+1
- p(x)=3×2+2x−5,x−3
- p(x)=5×3−2x+8,x+2
- p(x)=4×4−7x+6,x−1
- p(x)=x4+3×2−8,x+2
- p(x)=7×3−5×2+4,x−4
- p(x)=2×4+3x−5,x+3
- p(x)=9×2−11x+7,x−5
- p(x)=6×3+2×2−9,x+1
Section F – Use the Factor Theorem (10 Questions)
Determine whether the given polynomial is divisible by the given factor.
- x2−5x+6,x−2
- x2−9,x+3
- 2×2−8x+8,x−2
- x3−27,x−3
- x3+8,x+2
- 2×3+5×2−3,x+1
- 4×2−12x+9,x−23
- 3×3−24,x−2
- x2+11x+30,x+6
- 5×2−20x+15,x−1
Section G – Factorise Completely (15 Questions)
- x2−49
- x2+9x+20
- x2−12x+35
- 2×2+11x+15
- 3×2−15x+18
- x3−27
- x3+64
- x3−8
- x3+27
- 2×3+10×2
- 3×2−27
- 4×2−25
- 5×2−45x
- 6×2+18x
- 9×2−81
Section H – HOTS / Challenge Questions (20 Questions)
- Find the quadratic polynomial whose zeros are 5 and 8.
- Find the quadratic polynomial whose zeros are -4 and 7.
- Find the polynomial whose zeros are 3 and -9.
- If one zero of x2−kx+24 is 6, find k.
- If one zero of x2−11x+m is 3, find m.
- Find the value of k if (x−4) is a factor of x2+kx−20.
- Find k if (x+5) is a factor of x2+kx−30.
- If the sum of zeros is 9 and product is 20, form the polynomial.
- Form a quadratic polynomial whose zeros are 21 and 3.
- Form a polynomial with zeros -2 and -7.
- Find all zeros of x3−6×2+11x−6.
- Factorise x3+6×2+11x+6.
- Find the remainder when x5+2×3+7 is divided by x+1.
- Show that (x−5) is a factor of x3−2×2−5x+50.
- If x−3 is a factor of 2×3−kx2−5x+6, find k.
- Find all factors of x3−9×2+26x−24.
- Solve x2−14x+48=0.
- Solve 2×2−18x+40=0.
- Find the polynomial of degree 2 whose sum of zeros is 12 and product is 32.
- Create a quadratic polynomial whose zeros differ by 4 and whose sum is 10.
Class 10 Polynomials Worksheet – Answer Key (Part 1)
Questions 1–25
Section A – Degree of the Polynomial
- Degree = 3
- Degree = 5
- Degree = 2
- Degree = 6
- Degree = 1
- Degree = 0
- Degree = 8
- Degree = 7
- Degree = 9
- Degree = 4
Section B – Find the Zeros
- 8
- −15
- 5
- −4
- 5, −5
- 8, −8
- 8, 8
- 4, 5
- 6, 7
- 3, 8
- −3, −4
- 3, 7
- 3, 4
- 1, 3
- 10, −10
Class 10 Polynomials Worksheet – Answer Key (Part 2)
Questions 26–50
Section C – Verify the Relationship Between Zeros and Coefficients
For each quadratic (ax^2+bx+c):
- Sum of zeros = (-\frac{b}{a})
- Product of zeros = (\frac{c}{a})
- (x^2-5x+6)
- Zeros: 2, 3
- Sum = 5, Product = 6 ✓
- (x^2-7x+10)
- Zeros: 2, 5
- Sum = 7, Product = 10 ✓
- (x^2-8x+15)
- Zeros: 3, 5
- Sum = 8, Product = 15 ✓
- (x^2+9x+20)
- Zeros: −4, −5
- Sum = −9, Product = 20 ✓
- (x^2-12x+35)
- Zeros: 5, 7
- Sum = 12, Product = 35 ✓
- (2x^2-9x+10)
- Zeros: 2, 5/2
- Sum = 9/2, Product = 5 ✓
- (3x^2-13x+12)
- Zeros: 3, 4/3
- Sum = 13/3, Product = 4 ✓
- (4x^2-20x+24)
- Zeros: 2, 3
- Sum = 5, Product = 6 ✓
- (5x^2-15x+10)
- Zeros: 1, 2
- Sum = 3, Product = 2 ✓
- (6x^2-11x-10)
- Zeros: 5/2, −2/3
- Sum = 11/6, Product = −5/3 ✓
Section D – Polynomial Division
- Quotient = x + 4, Remainder = 0
- Quotient = x + 3, Remainder = 0
- Quotient = 2x + 5, Remainder = 0
- Quotient = 3x − 9, Remainder = 0
- Quotient = x² + 2x + 4, Remainder = 0
- Quotient = x² − 3x + 9, Remainder = 0
- Quotient = 2x² + 7x + 3, Remainder = 0
- Quotient = 3x² − 13x + 28, Remainder = −48
- Quotient = 4x² − 9, Remainder = 0
- Quotient = 5x² − 15x, Remainder = 15
Section E – Remainder Theorem
- 21
- 15
- 28
- −24
- 3
Class 10 Polynomials Worksheet – Answer Key (Part 3)
Questions 51–75
Section E – Remainder Theorem
- (p(x)=x^4+3x^2-8,; x+2)
Remainder = 20 - (p(x)=7x^3-5x^2+4,; x-4)
Remainder = 388 - (p(x)=2x^4+3x-5,; x+3)
Remainder = 148 - (p(x)=9x^2-11x+7,; x-5)
Remainder = 177 - (p(x)=6x^3+2x^2-9,; x+1)
Remainder = −13
Section F – Factor Theorem
Determine whether the given polynomial is divisible by the given factor.
- (x^2-5x+6,; x-2) → Yes
- (x^2-9,; x+3) → Yes
- (2x^2-8x+8,; x-2) → Yes
- (x^3-27,; x-3) → Yes
- (x^3+8,; x+2) → Yes
- (2x^3+5x^2-3,; x+1) → Yes
- (4x^2-12x+9,; x-\frac32) → Yes
- (3x^3-24,; x-2) → Yes
- (x^2+11x+30,; x+6) → Yes
- (5x^2-20x+15,; x-1) → Yes
Section G – Factorise Completely
- (x^2-49)
= ((x-7)(x+7))
- (x^2+9x+20)
= ((x+4)(x+5))
- (x^2-12x+35)
= ((x-5)(x-7))
- (2x^2+11x+15)
= ((2x+5)(x+3))
- (3x^2-15x+18)
= (3(x-2)(x-3))
- (x^3-27)
= ((x-3)(x^2+3x+9))
- (x^3+64)
= ((x+4)(x^2-4x+16))
- (x^3-8)
= ((x-2)(x^2+2x+4))
- (x^3+27)
= ((x+3)(x^2-3x+9))
- (2x^3+10x^2)
= (2x^2(x+5))
Class 10 Polynomials Worksheet – Answer Key (Part 4)
Questions 76–100
Section G – Factorise Completely
- (3x^2-27)
= 3(x-3)(x+3)
- (4x^2-25)
= (2x-5)(2x+5)
- (5x^2-45x)
= 5x(x-9)
- (6x^2+18x)
= 6x(x+3)
- (9x^2-81)
= 9(x-3)(x+3)
Section H – HOTS / Challenge Questions
- Zeros: 5 and 8
Polynomial: (x^2-13x+40)
- Zeros: −4 and 7
Polynomial: (x^2-3x-28)
- Zeros: 3 and −9
Polynomial: (x^2+6x-27)
- If one zero of (x^2-kx+24) is 6,
Other zero = 4
k = 10
- If one zero of (x^2-11x+m) is 3,
Other zero = 8
m = 24
- If ((x-4)) is a factor of (x^2+kx-20),
k = 1
- If ((x+5)) is a factor of (x^2+kx-30),
k = 1
- Sum of zeros = 9, Product = 20
Polynomial: (x^2-9x+20)
- Zeros = (\frac12) and 3
Polynomial: (2x^2-7x+3)
- Zeros = −2 and −7
Polynomial: (x^2+9x+14)
- Find all zeros of
(x^3-6x^2+11x-6)
Zeros: 1, 2, 3
- Factorise
(x^3+6x^2+11x+6)
= (x+1)(x+2)(x+3)
- Remainder when
(x^5+2x^3+7) is divided by (x+1)
Remainder = 4
- Show that ((x-5)) is a factor of
(x^3-2x^2-5x+50)
(p(5)=125-50-25+50=100)
Answer: ((x-5)) is not a factor. (The given question contains an error.)
- If ((x-3)) is a factor of
(2x^3-kx^2-5x+6)
(54-9k-15+6=0)
(45-9k=0)
k = 5
- Factorise
(x^3-9x^2+26x-24)
= (x-2)(x-3)(x-4)
- Solve
(x^2-14x+48=0)
x = 6, 8
- Solve
(2x^2-18x+40=0)
(x^2-9x+20=0)
x = 4, 5
- Sum of zeros = 12, Product = 32
Polynomial: (x^2-12x+32)
- Zeros differ by 4 and sum is 10
Zeros = 3 and 7
Polynomial: (x^2-10x+21)